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tankabanditka [31]
3 years ago
12

Select two numbers that make the inequality true. 2x - 3 > 1​

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer: 3 and 4

Step-by-step explanation:

2(3) - 3

6 - 3 = 3

3 > 1

2(4) - 3

8 - 3 = 5

5 > 1

marissa [1.9K]3 years ago
4 0

Answer:

3,4,5,6,..................any number bigger than 3 can be taken as the answer

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ASA

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Kite E F G H is inscribed in a rectangle. Points F and H are midpoints of sides of the rectangle, and creates a side length of x
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Answer:

5 units

Step-by-step explanation:

Let point O be the point of intersection of the kite diagonals.

|OF| = 2, |OH| = 5

|FH| = |OF| + |OH| = 2 + 5 = 7

FH and EG are the diagonals of the kite. Hence the area of thee kite is:

Area of kite EFGH = (FH * EG) / 2

Substituting:

35 = (7 * |EG|) / 2

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The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units

x = |GO| = |EO| = 5 units

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3 years ago
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Convert the function into intercept form. Show your work. y=-x^2+5x-36
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3 0
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Need help with homework
motikmotik

We have two points describing the diameter of a circumference, these are:

\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}

Recall that the equation for the standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Now, we replace and solve:

\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}

The center of the circle is (-8,-7), so:

\begin{gathered} h=-8 \\ k=-7 \end{gathered}

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

r^2=\Delta x^2+\Delta y^2

In this case, we will solve the delta with the center coordinate and the B coordinate.

\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}

Therefore, the equation for the standard form of a circle is:

\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}

In conclusion, the equation is the following:

(x+8)^2+(y+7)^2=25

4 0
10 months ago
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