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Rom4ik [11]
3 years ago
6

Variable c is 5 more than variable

Mathematics
2 answers:
olga_2 [115]3 years ago
8 0
More means to add NOT multiply
less means subtract therefore,

c= a+5
c= a-3
is the the correct choice

hope this helps
shutvik [7]3 years ago
7 0
First, let us restate the given conditions

c is 5 more than variable a ( c = a + 5)
c is also three less than variable a (c = a - 3)

Now, lets look at the answer choices and or given
c = a − 5 
c = a + 3
Here, c is 5 less than "a"...so automatically disqualified

a = c + 5
a = 3c − 3 
Here, we have to get "C" by itself in both top and bottom equation.
So,
Simplified version :
c = a - 5
Here, c is 5 less than "a"...so automatically disqualified


a = c − 5
a = 3c + 3
Here also, we have to get "C" by itself in both top and bottom equation.
So, 
simplified version:
c = a + 5
Here, c is 5 more than "a"...so we continue
c = (a - 3) / 3
Here, c is 3 less than "a" <u>divided by 3</u><u /> . So, this is not correct

c = a + 5
c = a − 3
Here, c is 5 more than "A"
Also, c is 3 less than "a"
Which satisfies the given.

 So, our answer is going to be the last one:
 
 c = a + 5
 c = a - 3
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Answer:

18

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5 0
2 years ago
Read 2 more answers
If sammmy has 5 alligators biting and each have 100 hunred teeth how many bite marks would he have?
posledela
Hello!

We are given that each of the 5 alligators has 100 teeth. We can use the following equation to find the total number of teeth and, by extension, the total number of bite marks:

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3 years ago
If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

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y(t) = C_1e^{5t}+C_2e^{6t}

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Answer:

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