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Lorico [155]
3 years ago
6

Kimberly and Mike have an equal amount of money. After Kimberly spent $50 and Mike spent $25, Mike's money is 50% more than Kimb

erly's. How much did Kimberly and Mike have at first?
Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer:

Kimberly and Mike had at first $100 each

Step-by-step explanation:

Assume that Kimberly and Mike each have $x

∵ Kimberly has $x

∵ Kimberly spent $50

- Find the reminder with Kimberly by subtracting 50 from x

∴ The money left with Kimberly = x - 50

∵ Mike has $x

∵ Mike spent $25

- Find the reminder with Mike by subtracting 25 from x

∴ The money left with Mike = x - 25

∵ Mike's money is 50% more than Kimberly's money

- That means Mike's money is more than Kimberly's money by

   50% of Kimberly's money

∴ x - 25 = (x - 50) + 50%(x - 50)

∵ 50% = \frac{50}{100} = 0.5

∴ x - 25 = (x - 50) + 0.5(x - 50)

- Simplify the right hand side

∴ x - 25 = x - 50 + 0.5x - 25

- Add the like terms in the right hand side

∴ x - 25 = 1.5x - 75

- Add 75 to both sides

∴ x + 50 = 1.5x

- Subtract x from both sides

∴ 50 = 0.5x

- Divide both sides by 0.5

∴ 100 = x

∵ x represents the amount of money that Kimberly and

   Mike each had at first

∴ Kimberly and Mike had at first $100 each

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A 45 foot ladder is leaning against a building. If the bottom of the ladder is 27 feet from the base of the building, how tall i
taurus [48]

Answer:

The height of building to the nearest foot is h = 36 foot

Step-by-step explanation:

We have given,

Length of ladder leaning against a building, l = 45 foot

Bottom length between ladder and the building , b = 27

Now, we need to find the height of building to the nearest foot.

Let the height of building be h.

Using Pythagoras theorem,

l^{2} = b^{2} +h^{2}

Here, l = 45 , b = 27 and h =?

So,

45^{2} = 27^{2} +h^{2}

h² = 45² - 27²

h = √(45² - 27²)

h = 36

The height of building to the nearest foot is h = 36 foot

8 0
3 years ago
Read 2 more answers
Please help me with precal
Doss [256]

Consider the function f(x)=\sqrt{x}. This function has:

  • the domain x\in [0,\infty);
  • the range y\in [0,\infty).

If the domain of unknown function is [a,\infty), then x\ge a or x-a\ge 0. This means that you have \sqrt{x-a} as a part of needed function.

If the range of unknown function is [b,\infty), then y\ge b. This means that you have to translate function b units up and then the expression of the function is

y=\sqrt{x-a}+b.

Answer: correct choice is B.

6 0
3 years ago
Help,anyone can help me do quetion.​
3241004551 [841]

Answer:

(a) x = 128^{o}

(b) x = 74^{o}

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

                        = 3 x 180

                        = 540^{o}

Thus,

x + 90 + 76 + 110 + 136 = 540^{o}

x + 412 = 540^{o}

x = 540^{o} - 412

x = 128^{o}

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

  = 142^{o}

y = 142^{o}

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = 540^{o}

z + 434 = 540^{o}

z = 540^{o} - 434

  = 106^{o}

z = 106^{o}

But, x + z = 180^{o}

Then;

x + 106^{o} = 180^{o}

x = 180^{o} - 106^{o}

  = 74^{o}

x = 74^{o}

7 0
3 years ago
Solve y
Ksivusya [100]

The value of y in -3 = 7\left(y-\dfrac97\right) is 6/7

<h3>How to solve for y?</h3>

The equation is given as:

-3 = 7\left(y-\dfrac97\right)

Open the bracket

-3 = 7y - 9

Add 9 to both sides of the equation

7y = 6

Divide both sides by 7

y= 6/7

Hence, the value of y in -3 = 7\left(y-\dfrac97\right) is 6/7

Read more about equations at:

brainly.com/question/2972832

#SPJ1

<u>Complete question</u>

Solve for y

-3 = 7\left(y-\dfrac97\right)

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2 years ago
PLEASE ANSWER ASAP FOR BRANLEST!!!!!!!!!!!!!!!
adoni [48]

Answer:

t = 8

Step-by-step explanation:

8 0
3 years ago
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