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zalisa [80]
2 years ago
9

Put these numbers in descending order 0.516 , 0.615 , 0.609 , 0.506

Mathematics
2 answers:
den301095 [7]2 years ago
8 0

Answer:

Step-by-step explanation:

0.615,  0.609, 0.516, 0.506

Margaret [11]2 years ago
8 0

The answer in descending order is 0.615, 0.609, 0.516 and 0.506

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A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel
kow [346]

Answer:

5P5×20P15

Step-by-step explanation:

A school bus has 25 seats, with 5 rows of 5 seats.

15 students from the first grade and 5 students from the second grade travel in the bus.

second-grade students occupy the first row.

The 5 students of second grade are to be seated in 5 seats,this can be done in:

5P5 ways where P is the permutation

Now 15 students from first grade are to be arranged in remaining 20 seats

This can be done in:

20P15 ways

Hence, total ways student can be seated is:

5P5×20P15

6 0
3 years ago
X is all of the following except<br> a term<br> a variable<br> a constant<br> an expression
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An expression is the answer
4 0
3 years ago
Which expression is equivalent to StartRoot 200 EndRoot?
Verdich [7]

Answer:

b)  √200 = 10√2

Step-by-step explanation:

Here, the given expression is: √200

Simplifying the given expression, we get:

200 = 2 x 2 x 2 x 5  x 5

⇒ 200  = (2)²  x (5) ²  x 2

Taking ROOT both sides, we get:\sqrt{200}  = \sqrt{(2)^{2}  \times (5)^{2}  \times  2}\\\implies \sqrt{200} = \sqrt{(2)^{2} } \times \sqrt{(5)^{2} } \times  \sqrt{(2) }  = 2 \times 5 \times \sqrt{2}\\ = 10 \sqrt {2}\\\implies \sqrt{200}  =  10 \sqrt {2}

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5 0
3 years ago
Read 2 more answers
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Karolina [17]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
What value of b will cause 16x ^ 2 + bx + 4 = 0 to have one real solution ?
bekas [8.4K]

Answer:

b  =  16

Step-by-step explanation:

16*x  + b*x  + 4  =  0

Solving for x we get:

x₁,₂  =   - b  ±  √  b² - 4*a*c   ] / 2*a         (1)

If we take a look to the square root

√ b² - 4*4*16      =  √ b²  - 256

if we make √ b²  - 256    = 0

b²  =  256       ⇒      b  =  16

Then equation (1) becomes:

x₁,₂  = ( - 16  ±  0  ) / 32

x  = -  1/2

6 0
2 years ago
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