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Alex73 [517]
3 years ago
8

Write method reverseString, which takes a string str and returns a new string with the characters in str in reverse order. For e

xample, reverseString("ABCDE") should return "EDCBA".
Complete the reverseString method below by assigning the reversed string to result.

/** Takes a string str and returns a new string

* with the characters reversed.

*/

public static String reverseString(String str)

{

String result = "";

return result;

}
Computers and Technology
1 answer:
son4ous [18]3 years ago
3 0

Answer:

The method written in Java is as follows:

public static String reverseString(String str){

    String result = "";

    int lentt = str.length();

    char[] strArray = str.toCharArray();

       for (int i = lentt - 1; i >= 0; i--)

           result+=strArray[i];

    return result;

}

Explanation:

This defines the method

public static String reverseString(String str){

This initializes the result of the reversed string to an empty string

    String result = "";

This calculates the length of the string

    int lentt = str.length();

This converts the string to a char array

    char[] strArray = str.toCharArray();

This iterates through the char array

       for (int i = lentt - 1; i >= 0; i--)

This gets the reversed string

           result+=strArray[i];

This returns the reversed string            

    return result;

}

<em>See attachment for full program that includes the main method</em>

Download txt
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<h3>What are Elegant mathematical technique?</h3>

ALGORITHM :

1. Take the values of all coefficients and SET flag = FALSE

2. Run a FOR loop for x in range (-10, 11). 11 won't be included.

2a. Inside the first FOR, start the y FOR loop in range(-10,11). 11 won't be included

2b. Inside the y FOR loop, check IF for a particular value of x and y both the equations satisfied.

2c. If yes, set flag TRUE and print values of x and y.

2d. ELSE the flag stays FALSE.

END FOR Y

END FOR X

3. Check if flag = FALSE, then print NO SOLUTION

PYTHON CODE :

a=int(input()) #taking input for each coefficient

b=int(input())

c= int(input())

a1= int(input())

b1= int(input())

c1= int(input())

flag = False

for x in range(-10,11): #checking for all values of x in range -10 to 10

for y in range(-10,11): #checking for all values of x in range -10 to 10

if (a  x + b  y – c == 0) and (a1*x + b1*y - c1 == 0) : #checking if the x and y values satisfy the equation

flag = True #setting the flag if solution is found

print('Solution : x = {-10, 10}, y = {-10, 10}'.format(x,y)) #if they satisfy print x & y

if flag = False : #if flag stays false, that means there is no solution

print('No solution')

OUTPUT : The output is given below.

More about the Elegant mathematical technique link is given below.

brainly.com/question/27934739

#SPJ1

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3 years ago
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