Hello, I have a problem:

Mathematics

1 answer:

Mamont248 [21]3 years ago

8 0

You could get 169 mixtures

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We have two urns. The rst urn contains two balls labeled 1 and 2. The second urn contains three balls labeled 3, 4 and 5. We cho

labwork [276]

Answer:0.1667

Step-by-step explanation:

Given

we have two urns labelled let say A and B

Urn A has balls labelled as 1 and 2

Urn B has balls labelled as 3,4 and 5

Probability of picking the number 5 ball $=Probability\ to\ choose\ Urn\ B\times Probability\ to\ choose\ no\ 5 ball$

Probability to choose Urn B $=\frac{1}{2}$

Probability to choose no 5 ball from Urn B $=\frac{1}{3}$

Required Probability $=\frac{1}{2}\times \frac{1}{3}=0.166$

6 0

3 years ago

I don’t understand this problem please help

saveliy_v [14]

Answer: Anika 7 par johan 8 par Seamus 9 par

Step-by-step explanation:

7 0

2 years ago

Please do synthetic (8x³ +2x + 3) ÷ (x -1) thx

AURORKA [14]

Hello There!

First write down the first coefficient without changes as a table
Next you multiply the left part of the table by the last entry.
The quotient is $8 x^{2} + 8x + 10$ and the remainder would be 13.
Therefore $\frac{8 x^{3 }+ 2x + 3 }{x -1}$ = $8 x^{2} + 8x + 10 + \frac{13}{x - 1}$

Answer is $8 x^{2} + 8x + 10 + \frac{13}{x - 1}$

Hope This Helps You!
Good Luck :)

5 0

3 years ago

Read 2 more answers

What is the place value of the 2 in the following number?

Akimi4 [234]

Answer:

tenths

Step-by-step explanation:

0.2 is two tenths

so twotenths

4 0

3 years ago