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Goshia [24]
3 years ago
5

The length of a rectangle is 2 ft longer than its width. if the perimeter of the rectangle is 32 ft , find its area.

Mathematics
1 answer:
mash [69]3 years ago
3 0
The length of would be 9 and the width 7, resulting in an area of 63
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Montano1993 [528]
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The length of a rectangle is 3 more inches than the width. Find the length and width of the rectangle is the perimeter of the re
n200080 [17]

Part A:

Let the width of the rectangle be = x inches

As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches

Perimeter is given as = 54 inches

Perimeter = 2(l+b)

Equation becomes:

2(x+3+x)=54

2(2x+3)=54

Part B:

Solving the equation we get

4x+6=54

4x=54-6

4x=48

x=12

Hence, the width of the rectangle is 12 inches

Length = x+3 = 12+3 = 15 inches

Hence, length of the rectangle is 15 inches.


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