Determine the probability of having 0 girlsgirls and 3 boys in a 3-child family assuming boys and girls are equally likely. wha t would be the fraction?
2 answers:
Answer:
1/8
Step-by-step explanation:
Let
Event A: The first-born is a boy. Event B: The second-born is a boy. Event C: The third-born is a boy.
Considering one birth, the probability of having a boy is 0.5 or 1/2 .
Each birth is independent of the previous one. <em>The probability that independent events occur is equal to the product of the individual probabilities.</em>
P (A and B and C) = P(A).P(B).P(C) = 1/2 . 1/2 . 1/2 = 1/8
3/3 is the answer to your question.
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4
The function of 5 (or y when x is 5) can not be determined with this little information.
There are 2 dollars so that would equal 20 dimes.
Proof:
10 cents = a dime
20 x 10 = 200 = 2 dollars
__
There are 35 cents to that would equal 3 dimes and 1 nickel.
Proof:
10 cents = a dime
5 cents = a nickel
3 x 10 = 30
1 x 5 = 5
__
So the final answer would be 23 dimes and 1 nickel .
Answer:
C
Step-by-step explanation:
Answer:
Positive: (-3)4,(-1)2,(-4)8
Negative:(-10)5,(-2)9,(-6)3
Step-by-step explanation:
