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mel-nik [20]
2 years ago
15

A school wants to investigate the amount of exercise students do.

Mathematics
1 answer:
taurus [48]2 years ago
7 0

Answer:

100-200     Step-by-step explanation: yes 600 is half the students most of them are going to be in class

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two sides of a triangle are 4 and 6 the third side cant be what A 2 b 4 c 6 d 8 please respond asap ​
noname [10]

Answer:

it’s b.4

hopes this help you

8 0
3 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
Hi can anyone plz help me with this and can you explain how you got it ​
zloy xaker [14]

Answer:

What to prove, solve for?

6 0
3 years ago
Read 2 more answers
The graph of the function f(x) = ax2 + bx +C
morpeh [17]

Answer:

The axis of symmetry is  -b/2a

The x-intercept shown is 3 units away from the axis of symmetry.

The other x-intercept also must be 3 units away from the axis of symmetry but on the opposite side.

Subtract 3 from the axis of symmetry.

The other x-intercept is  (-b/2a-3,0)

Step-by-step explanation:

7 0
3 years ago
You have inherited land that was purchased for $25,000 in 1970. The value of the land has appreciated by
Darina [25.2K]

Answer:

Future value of land = 25,000[1.04]³⁰

Future value of land = $81,084 (Approx.)

Step-by-step explanation:

Given:

Purchase cost of land in 1970 = $25,000

Application rate = 4% per year

Find:

Price of land in 2000

Computation:

Number of year = 2000 - 1970 = 30 year

Future value of land = [Purchase cost of land][1+Application rate]ⁿ

F = P[1+r]ⁿ

Future value of land = 25,000[1+4%]³⁰

Future value of land = 25,000[1+0.04]³⁰

Future value of land = 25,000[1.04]³⁰

Future value of land = 25,000[3.24339]

Future value of land = 81,084.75

Future value of land = $81,084 (Approx.)

5 0
3 years ago
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