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Vedmedyk [2.9K]
3 years ago
5

The graph of f(x) = x3 − 7x − 6 is shown. Based on the graph, what are all of the solutions to f(x) = x3 − 7x − 6? x = −6 x = −2

, −1 x = −2, −1, 3 x = −6, −2, −1, 3
Mathematics
2 answers:
pogonyaev3 years ago
4 0
F(x)=x^3-7x-6  Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P

x-(f(x)/(dy/dx))

x-(x^3-7x-6)/(3x^2-7)

(2x^3+6)/(3x^2-7), letting x1=0

0, -6/7, -.988, -.9999, -.99999999999, -1

(x^3-7x-6)/(x+1)

x^2 r -x^2-7x-6
-x   r  -6x-6
-6   r  0

(x+1)(x^2-x-6)=0

(x+1)(x-3)(x+2)=0

x= -2, -1, 3 


emmainna [20.7K]3 years ago
3 0

Answer:

c

Step-by-step explanation:

e2020

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Solve for m
MakcuM [25]

Answer:

m = 29/48

Step-by-step explanation:

Given that

x₂ = (y₂-y₁) +10 →(1

y₂ = y₁-x₁ → (2

y₁= 37

x₁ = 29

Now substitute the value of x₁ and y₁ into equation 2

y₂ = 37-29

y₂ = 8

Now substitute the value of y₂ and y₁ into equation 1

x₂ = (8-37) +10

x₂ = -19

As we know the slope (m) can be calculated as follows

m =(y₂ - y₁)/(x₂ - x₁)

m = (8- 37)/(-19 - 29)

m = (-29)/(-48)

m = 29/48

So our slope is 29/48



3 0
3 years ago
Trials in an experiment with a polygraph include results that include cases of wrong results and cases of correct results. Use a
hram777 [196]

Answer and Step-by-step explanation:

This is a complete question

Trials in an experiment with a polygraph include 97 results that include 23 cases of wrong results and 74 cases of correct results. Use a 0.01 significance level to test the claim that such polygraph results are correct less than 80​% of the time. Identify the null​hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method. Use the normal distribution as an approximation of the binomial distribution.

The computation is shown below:

The null and alternative hypothesis is

H_0 : p = 0.80

Ha : p < 0.80

\hat p = \frac{x}{ n} \\\\= \frac{74}{97}

= 0.7629

Now Test statistic = z

= \hat p - P0 / [\sqrtP0 \times (1 - P0 ) / n]

= 0.7629 - 0.80 / [\sqrt(0.80 \times 0.20) / 97]

= -0.91

Now

P-value = 0.1804

\alpha = 0.01

P-value > \alpha

So, it is Fail to reject the null hypothesis.

There is ample evidence to demonstrate that less than 80 percent of the time reports that these polygraph findings are accurate.

5 0
3 years ago
What is 2/5 simplified?
zmey [24]
2/5 van not be simiplified because 2 and 5 dont have a common factor lower than them
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Can someone help me with this please???
AysviL [449]

Answer:

diarrhea

Step-by-step explanation:

6 0
3 years ago
Please help
gregori [183]
A. Zero points of intersection

the lines are parallel
7 0
3 years ago
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