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Vedmedyk [2.9K]
3 years ago
5

The graph of f(x) = x3 − 7x − 6 is shown. Based on the graph, what are all of the solutions to f(x) = x3 − 7x − 6? x = −6 x = −2

, −1 x = −2, −1, 3 x = −6, −2, −1, 3
Mathematics
2 answers:
pogonyaev3 years ago
4 0
F(x)=x^3-7x-6  Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P

x-(f(x)/(dy/dx))

x-(x^3-7x-6)/(3x^2-7)

(2x^3+6)/(3x^2-7), letting x1=0

0, -6/7, -.988, -.9999, -.99999999999, -1

(x^3-7x-6)/(x+1)

x^2 r -x^2-7x-6
-x   r  -6x-6
-6   r  0

(x+1)(x^2-x-6)=0

(x+1)(x-3)(x+2)=0

x= -2, -1, 3 


emmainna [20.7K]3 years ago
3 0

Answer:

c

Step-by-step explanation:

e2020

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The third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.

We are given that:

2nd term of geometric progression = 1 / 18

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Now, we can also write it as:

2nd term = a r ( where r is the common ratio and a is the initial term.)

a r = 1 / 18

5th term = a r⁴

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Now divide 5th term by 2nd term, we get that:

a r⁴ / a r = ( 4 / 243 ) / ( 1 / 18 )

r³ = 72 / 243

r³ = 8 / 27

r = ∛ (8 / 27)

r = 2 / 3

3rd term = a r²

a r² = a r × r

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Therefore, the third term of the geometric progression will be 1 / 27 with common ratio 2 / 3.

Learn more about geometric progression here:

brainly.com/question/24643676

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Your question was incomplete. Please refer the content below:

The 2nd and 5th term of a GP are 1/18 and 4/243 respectively find the 3rd term

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