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3 years ago

I’m stuck on this please someone help

Mathematics

1 answer:

kakasveta [241]3 years ago

6 0

Answer: $\bold{a_{n+1}=\dfrac{1}{2}a_n}$

<u>Step-by-step explanation:</u>

Term-to-term rule is also called the recursive rule.

The recursive rule for a geometric sequence is: $a_{n+1}=a_n\cdot r$ where

$a_n\ \text{is the previous term}$
r is the common ratio

The common ratio (r) is the second term divided by the first term <em>(which is the same ratio for each term divided by its previous term) </em>

In the given sequence {64, 32, 16, 8, 4}, $r=\dfrac{32}{64}\quad \rightarrow \quad r=\dfrac{1}{2}$

So, the recursive rule is: ${a_{n+1}=a_n\cdot \dfrac{1}{2}$

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Find the slope of the line that passes through (4, 9) and (6, 10).

kramer

Step-by-step explanation:

Slope (m) =ΔYΔX=12=0.5θ =arctan(ΔY)ΔX=26.565051177078°ΔX = 6 – 4 = 2ΔY = 10 – 9 = 1Distance (d) = √ΔX2 + ΔY2 = √5

= 2.2360679774998

4 0

3 years ago

ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe

xxMikexx [17]

Answer:

$654.16-2.02\frac{165.23}{\sqrt{42}}=602.66$

$654.16+2.02\frac{165.23}{\sqrt{42}}=705.66$

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=654.16$ represent the sample mean

$\mu$ population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that $t_{\alpha/2}=2.02$