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balandron [24]
3 years ago
7

QUESTION: (whats the symbol of integers and whats the tabular form of integers) PLS TELL ME CORRECT ANSWER ​

Mathematics
1 answer:
Olin [163]3 years ago
5 0

Answer:

Symbol of integer =Z

Roster or tabular form: In roster form, all the elements of a set are listed, the elements are being separated by commas and are enclosed within braces { }.

For Example:{3,0-1,}

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14 fr to 21 ft ( simply )
zimovet [89]
If you're asking the difference between 14 ft and 21 ft your answer is 7 ft, just subtract 14 from 21
6 0
3 years ago
Jodie wants to raise money for a school trip by selling raffle tickets at a basketball game. She sells each ticket for 50 cents,
wel

Answer:

250 dollars

Step-by-step explanation:

t = tickets

t = 200

Two and a half rolls tickets = (200 x 2) + 200/2) = 400 + 100 = 500

500 tickets x 50 cents = 25000 cents

convert cents to dollars (move decimole point over left 2 units)

25000 = 250 dollars

6 0
3 years ago
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vodomira [7]

Answer:

4.) 12

5.)1.67

Step-by-step explanation:

5 0
3 years ago
Please help, please help
zmey [24]
Answers:
x=22
x+4=26
6x=132

Explanation:
We learned from the question that all of the angles in a triangle add up to 180 degrees.

180=angle+angle+angle

When we plug in the values that the question gives us for the angles, we get this equation:

180=x+6x+(x+4)

After solving this equation, we get 22 as the value of x (The process of solving that equation is in the picture attached).

To solve for (x+4), we plug in the value of x, which is 22 and add 4.

(x+4)
=(22+4)
=26

And finally, to solve for 6x, we plug in 22 again:

6x
=6*22
=132

Hope this helps!

7 0
3 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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