We find the length of AD using the similarity of right triangle property. See image attached.
AD² = BD × CD
AD² = 9 × 36
AD² = 324
AD² = 18²
AD = 18
The length of AD is 18 units
Answer: 5:3, 5/3, 5 to 3
Step-by-step explanation:
The area of the base (six triangles with a base 15m and a height 7.5√3m):
The area of side walls (six triangles with a base 15m and a height 12m)
The surface area:
Answer:
0.9
Step-by-step explanation:
3.13-2.23=0.9
Mr edwards = Mr r x 2
Mr r = Mr p - 3 = Mr e ÷ 2. Mr p = 30
Mr e + Mr r = 81. Mr e = 54
Mr p = Mr r + 3. Mr r = 27
Mr Edwards = 2(Mr p - 3)
Mr e = 2(mr p) - 6
Mr r = [2(Mr p) -6] ÷ 2
Mr r = [2( Mr r + 3) - 6] ÷ 2
2(Mr r) + (Mr p - 3) = 81
2(Mr p -3) + (Mr p - 3) = 81
3(Mr p - 3) = 81
3(Mr p) - 9 = 81. Hope this helps!!!
3(Mr p) + 9 = 81 + 9
3(Mr p) = 90
Mr p = 90 ÷ 3
Mr p = 30