Answer:
4910.8672217
Step-by-step explanation:
I dont have a step by step, i am so sorry
Answer:

Step-by-step explanation:
Total possibilities when we a roll a die at a time are 6
given we should have four for first time and then three
let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is
PROBABILITY=
Favourable chances=1
Total chances=6
Probability=
the prabability to get 4 in first roll is
.
let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is
Favourable chances=1
total chances=6
probability=
the probability to get 3 in second roll irrespective of first one is 
the probability to get 4 in first time and then 3 is
The probability to occur both events at a time is multiplication of individual probabilities
So,
probablility to get 4 in first roll=
probability to get 3 in second roll=
probability to occur both at a same time is =

=
The only way to do this one is by long division which I can't figure out how to show here. There are some great examples online if you google long division with polynomials.
The answer is 3x^2+3x+3 with a remainder of 5x+6 who's is usually shown as (5x+6)/2x^2 +2x+4 which was the divisor g(x).
The answer is 28.67 with the tax rate and total amount
Of your numbers listed, 29 and 41 are the lengths of the hypotenuse of a Pythagorean triple.
Those triples are
(20, 21, 29)
(9, 40, 41)
_____
The On-Line Encyclopedia of Integer Sequences (OEIS) lists the hypotenuses of primitive triples as sequence number A020882.