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kramer
4 years ago
15

3(x+2)=2(x+5) i really need help

Mathematics
2 answers:
Ivan4 years ago
6 0

Answer:

x=4

Step-by-step explanation:

3(x+2)=2(x+5)

opening brackets

3x+6=2x+10

3x-2x=10-6

1x=4

MrRa [10]4 years ago
5 0

Answer:

x=4

Step-by-step explanation:

3(x+2)=2(x+5)

Clear the brackets by multiplying

3x+6=2x+10

Collect like terms

3x-2x=10-6

x=4

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Answer:

13

Step-by-step explanation:

8--5 = 8 + 5 = 13

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Semmy [17]

fff

f(x) = e^x sin (x)

To find increasing and decreasing intervals we take derivative

f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)

Now we set the derivative =0  and solve for x

e^x(sinx+cosx)=0

sinx + cosx =0

divide whole equation by cos x

\frac{sinx}{cosx} + \frac{cosx}{cosx} =0

tanx +1 =0

tanx = 1

x=\frac{3\pi }{4} and  x=\frac{7\pi}{4}

Now we pick a number between 0 to  \frac{3\pi }{4}

Lets pick  \frac{\pi }{2}

Plug it into the derivative

f'(x) =e^{\frac{\pi }{2}}(sin(\frac{\pi}{2})+cos(\frac{\pi }{2}))

= 4.810 is positive

So the graph of f(x) is increasing on the interval [0, x=\frac{3\pi }{4})

Now we pick a number between   \frac{7\pi}{4} to 2pi

Lets pick  \frac{11\pi}{6}

Plug it into the derivative

f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))

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So the graph of f(x) is increasing on the interval (\frac{7\pi }{4}, 2\pi)

Increasing interval is (0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)

Decreasing interval is (\frac{3\pi}{4}, \frac{7\pi}{4})

(b)

The graph of f(x) increases and reaches a local maximum at x=\frac{3\pi}{4}

The graph of f(x) decreases and reaches a local minimum at x=\frac{7\pi}{4}

(c)

f(0) = 0

f(2\pi)=0

f(\frac{3\pi }{4})=7.46

f(\frac{7\pi}{4})=-172.64

Here global maximum at x=\frac{3\pi}{4}

Here global minimum at x=\frac{7\pi}{4}


3 0
4 years ago
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Your equation:<br><img src="https://tex.z-dn.net/?f=%20%7B3%7D%5E%7B%3F%7D%20%20%5Ctimes%20%20%7B3%7D%5E%7B%3F%7D%20%20%5Cdiv%20
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Steps

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How do I do this question?
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Answer:

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