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ElenaW [278]
3 years ago
11

What value is equivalent to 52 + 53 − 54?

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

51

Step-by-step explanation:

simplify the equation and you get the answer

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Which relation is also a function (i can’t get this wrong please help) 15 points
Nuetrik [128]

Answer:

The answer is d

Step-by-step explanation:

this is because a , b and c all have multiple x vales with more then one y value .

6 0
2 years ago
Y=(1/2)^x +2. What is the horizontal asymptote of this function?
professor190 [17]
\lim_{x\to -\infty} \left(\frac{1}{2}\right)^x+2=\infty+2=\infty\\
\lim_{x\to \infty} \left(\frac{1}{2}\right)^x+2=0+2=2\\

There is one-sided horizontal asymptote y=2
6 0
3 years ago
5t-14=-14<br> solve the equation for t
ikadub [295]

Hi there!


Before we begin, let's rewrite your equation. :)


5t - 14 = -14


Step 1) Add 14 to both sides.


5t - 14 + 14 = -14 + 14 5t = 0


Step 2) Divide both sides by 5.


\frac{5t}{5} =  \frac{0}{5}


t = 0


Final Answer -


t = 0


Hope this helps!

Message me if you need anymore help! :D


3 0
3 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2&#10;\\\\\\\&#10;[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]&#10;\\\\\\&#10;2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)&#10;\\\\\\&#10;\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}&#10;\\\\\\&#10;\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}&#10;\\\\\\&#10;\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}&#10;\\\\\\&#10;\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
If 3x + 2 = 4, what is the value of 6x - 4?<br> 2<br> 8<br> 0<br> -2
Sladkaya [172]

Answer:

0

Step-by-step explanation:

3x + 2 = 4

4-2 = 3x

2 = 3x

x = 2/3

2/3 x 6 = 12/3 = 4 - 4 = 0

8 0
3 years ago
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