The 30:60:90 proportion is 1:sqrt 3: 2
So,
x = 10/2
x = 5
y = 10/sqrt 3
Finding the area:
1/2 * 5 * 10/sqrt 3
25/sqrt 3
Hope this helps!
Answer:
Step-by-step explanation:
AD = 4
AC = 11
DC = 11 - 4 = 7
First, find BD using the right triangle altitude theorem:
Plug in the values
Use pythagorean theorem to find x:
x² = AD² + BD²
Plug in the values
Take the square root of both sides
(6/13)/(6/12)= (6/13)*(12/6)= 12/13
This rule for division applies to all fraction divisions
1/4 the students in study hall (per 7) = 16
16*4 = 64 students in study hall.
<span>Hope I helped! (Pick my answer as brainliest!)</span>
Answer:
δL/δt = 634,38 ft/s
Step-by-step explanation:
A right triangle is shaped by ( y = distance between aircraft and ground which is constant and equal to 405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f and the line between the aircraft and the person. Then we can use Pythagoras theorem and write
L ( distance between aircraft and person )
L² = x² + y² or L² = x² + (405)²
Taken partial derivatives with respect to t we get:
2*L*δL/δt = 2*x*δx/t + 0
Then L*δL/δt = x*δx/dt
At the moment of the aircraft passing over the tower
x = 3040 ft δx/δt = 640 ft/s and L = √ ( 3040)² + (405)²
So L = √9241600 + 164025 L = √9405625 L ≈3066,9 ft
Then:
δL/δt = 3040*640/ 3066,9 units [ ft * ft/s / ft ] ft/s
δL/δt = 634,38 ft/s
