X + y = 15
xy = -312
x + y = 15
x - x + y = -x + 15
y = -x + 15
xy = -312
x(-x + 15) = -312
x(-x) + x(15) = -312
-x² + 15x = -312
-x² + 15x + 312 = 0
-1(x²) - 1(-15x) - 1(312) = 0
-1(x² - 15x + 312) = 0
-1 -1
x² - 15x + 312 = 0
x = -(-15) ± √((-15)² - 4(1)(312))
2(1)
x = 15 ± √(225 - 1248)
2
x = 15 ± √(-1023)
2
x = 15 ± 31.984i
2
x = 7.5 ± 15.992
x = 7.5 + 15.992 or x = 7.5 - 15.992
x = 23.492 or x = -8.492
x + y = 15
23.492 + y = 15
- 23.492 - 23.492
y = -8.492
(x, y) = (23.492, -8.492)
or
x + y = 15
-8.492 + y = 15
+ 8.492 + 8.492
y = 23.492
(x, y) = (-8.492, 23.492)
The two numbers that add up to 15 and mutliply to -312 are -8.492 and 23.492.
Answer:
maxuin 10
Step-by-step explanation:
answer: D = 1
Isolate the variable by dividing each side by factors that don't contain the variable. 7 (2d - 1) + 5 (2 - 3d) = 2d
Answer:
x ≤ 3
Step-by-step explanation:
Answer:
Step-by-step explanation:
must be r and s
because right at in middle of the distance between them is 0
