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Aloiza [94]
3 years ago
12

Given that the first term is LaTeX: t_1=5t 1 = 5, and the recursive definition is LaTeX: t_{n+1}=3\cdot t_nt n + 1 = 3 ⋅ t n, wh

at would be the second term (i.e. LaTeX: t_2t 2)
Group of answer choices

3

5

8

15
Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

  • <u>Fourth choice: 15</u>

Explanation:

The question is: given that the first term is    t_1=5    and the recursive definition is    t_{n+1}=3\cdot t_n    , what would be the second term (i.e.    t_2    )

A recursive defintion or recursive formula is an equation (a rule) that you apply over a term to find the next term, and so you can use it repeatedly to find the successive terms of a series.

In this case, your rule is that you multiply each term by 3, starting from 5.

Thus:

  • First term:     t_1=5

  • Second term = 3 × first term :    t_2=3\cdot t_1=3\cdot 5=15

Hence, your answer is 15 (the fourth choice).

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A school has 20
motikmotik

Answer:

One forth of 20 is 5, so there are 5 kindergarten and first grade classrooms.

5 x 2 is 10 so there are 10 second and third grade classrooms.

10 + 5 is 15.

20 - 15 is 5.

There are 5 forth and fifth grade classes.

Step-by-step explanation:

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Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

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Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

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3 years ago
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Dmitrij [34]
I know you probably dont need this anymore but the answer is

1 = gerund

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3 = participle

hope i helped and good luck ;D
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Answer:

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Step-by-step explanation:

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Rewrite</u>

<em>Find slope-intercept form</em>

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