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shtirl [24]
4 years ago
5

what is the percentage of this question, After reading a book for English class, 100 students were asked whether or not they enj

oyed it. Nine twenty-fifths of the class did not luke the book. How many students liked the book?

Mathematics
1 answer:
kogti [31]4 years ago
3 0
100 divided by 25 = 4 so 4 x16 is 64 so the answer is 64 students or 16 25ths
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Write the equation of the quadratic given the following information:
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<span>y=a((x-h)^2)+k
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3 years ago
Select the proper order from least to greatest for 1/2, 5/6, 2/7, 4/2. A. 2/7, 1/2, 5/6, 4/2. B. 2/7, 5/6, 1/2, 4/2 C. 4/2, 2/7,
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3 0
3 years ago
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Five years after 650 high school seniors graduated, 400 had a college degree and 310 were married. Half of the students with a c
DedPeter [7]

Answer:

The probability that a student has a college degree or is not married is 0.8308.

Step-by-step explanation:

The information provided is:

Total number of high school seniors (<em>N</em>) = 650.

Number of seniors with a college degree (<em>n</em> (C)) = 400.

Number of seniors who were married, (<em>n</em> (M)) = 310.

Consider the Venn diagram below.

The probability of an event, say E, is the ratio of the favorable outcomes of <em>E</em> to the total number of outcomes of the experiment.

That is,

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes of <em>E</em>

N = total number of outcomes of the experiment.

The probability of the union of two events is:

P(A\cup B)=P(A)+P(B)-P(A\cap B)=\frac{n(A)+n(B)-n(A\cap B)}{N}

Compute the probability that a student has a college degree or is not married as follows:

P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}

From the Venn diagram:

n (C) = 400

n (M^{c}) = N - n (M) = 650 - 310 = 340

n (C ∩ M^{c}) = 200

The value of P (C ∪ M^{c}) is:

P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}=\frac{400+340-200}{650}=0.83077\approx0.8308

Thus, the probability that a student has a college degree or is not married is 0.8308.

6 0
3 years ago
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