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Rus_ich [418]
3 years ago
8

Is -31 >or equal to -3

Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0

Answer:

-3 is greater than -31

asdfghjkl

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McDonalds sells quarter-pound cheeseburgers for .99 cents last saturday.they sold 310 of these cheeseburgers. how many pounds of
Anvisha [2.4K]
The first thing you should do is calculate how many pounds of cheese a hamburger has
 1 hamburger = 1/4 pound of cheese.
 Then, you can make a rule of three to know how many pounds of cheese were sold:
 1 ---> 1/4
 310 ---> x
 Clearing x we have:
 x = ((310) / (1)) * (1/4) = 77.5
 Answer
 they sell last saturday 77.5 pounds of cheese
4 0
3 years ago
Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for r
butalik [34]

The missing part of the question is show in bold format.

Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for rolling it

once. Your probability model shows a probable outcome of 1/6 for each of the numbers on the cube, 1 chance for all any of the 6 numbers.

You roll it 500 times and get the following data:

Outcome 1 2 3 4 5 6

Frequency 77 92 75 90 76 90

Exercises 1–2

1. If the equality model was correct, about how many of each outcome

would you expect to see if the cube is rolled 500 times

2. Based on the data from the 500 rolls, how often were odd numbers observed? How often were even numbers observed?

Answer:

Step-by-step explanation:

1.

If the equally likely model was correct,  about how many of each outcome

would you expect to see if the cube is rolled 500 times.

The probability of rolling any of the numbers from 1 to 6 is  p(1/6)

The number of each of the outcomes expected to be seen in 500 rolls of the number cube is np

= 500 * \frac{1}{6}  \\ \\ = \frac{500}{6} \\ \\  = 83.333 \\ \\ \approx 83

2.  From the given data in the roll;

The odd numbers 1, 3 and 5, were obtained at  77, 75 and 76 times respectively.

Thus, the total number of times odd number were rolled = 77 + 75 + 76 = 228

Probability of an odd number turning up = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{228}{500}

= 0.456

= 45.6%

The even numbers, 2, 4 and 6, were obtained 92, 90 and 90 times respectively.

The total number of times even number were rolled = 92 + 90 + 90 = 272

Probability of an even number turning up  = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{272}{500}

= 0.544

= 54.4%

4 0
3 years ago
write a conjecture as to the number of sides as compared to the number of triangles formed when drawing diagonals from one verte
zmey [24]

Answer:The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the previous term as follows: if the previous term is even, the next term is one half the previous term. If the previous term is odd, the next term is 3 times the previous term plus 1.

Step-by-step explanation :an opinion or conclusion formed on the basis of incomplete information.

8 0
2 years ago
I just need the 4th not the 3rd please help I will give you BRAINLIEST!!!!​
mina [271]

Answer:

See attached

Step-by-step explanation:

The answer is in the picture below

3 0
2 years ago
Help me on geometry??
algol13

Answer:

15. ∠ABE = 50°

16. ∠EBD = 10n - 19

Step-by-step explanation:

If $ \overline{\textbf{BE}} $ bisects ∠ABD then we have ∠ABE = ∠DBE

So, we will have: (6x + 2)° = (8x - 14)°

⇒ 6x + 2 = 8x - 14

⇒ 8x - 6x = 14 + 2

⇒ 2x =16

⇒ x = 8

∴ ∠ABE = 6(8) + 2

= 48 + 2

= 50°

∴∠ABE = 50°

16. If $ \overline{\textbf{BE}} $ bisects ∠ABD then ∠ABE + ∠EBD = ∠ABD

⇒(12n - 8) + ∠EBD = (22n - 11)

⇒ ∠EBD = 22n - 11 - 12n + 8

⇒ ∠EBD = 10n - 3

Hence, the answer.

7 0
2 years ago
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