d = 3 , a₁₂ = 40 and S = 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:
Step-by-step explanation:
To solve for the variable , start by subtracting from both sides of the equation:
Then, subtract from both sides of the equation:
Therefore,
-
To check your work, simply substitute the solved value of into the initial equation:
Multiply:
Add:
Since both sides of the equation are equal to each other, our solution is correct!
The volume would be 5 because in order to find volume you need to divide mass over density. V=m/d
7.9 meters if u add the mesurements if thats what ur looking for
Answer:
0
Step-by-step explanation:
12 = 24x +12
x = 0
Good luck
You can do it!