I don’t know if this is correct !!!!!!!!!! Please answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

aleksley [76]3 years ago

7 0

Answer: They are related by the AAS postulate and they can be proven congruent.

Step-by-step explanation: You can see that one of the lines on each of the triangle has that little tick which means those lines are congruent. You can also see that for two of the angles one of them has one arc and the other has two arcs for BOTH triangles which makes those two angles congruent. Two angles and one side congruent makes the triangles congruent by the AAS postulate.

I hope I helped! :)

You might be interested in

If log10 y = 2. what does y equal?

lys-0071 [83]

Answer:

$log_{10} (100) = 2$

Step-by-step explanation:

Here, the given expression is:

$log_{10} (y) = 2$

Now, by logarithm rules, we know

if $log_{b}(x) = z$

, then x = $b^{z}$

Comparing here, b = 10 and z = 2

⇒ y = $10^{2} = 100$

or, $log_{10} (100) = 2$

6 0

3 years ago

Consider the ratio 3:5. Can you create an equivalent ratio by adding the same number to each quantity in the ratio? Explain

iragen [17]

Yes because the unit rate would be 1:2 and that's the rate of change in which 3:5 has.
HOPE IT HELPS!!

4 0

3 years ago

Read 2 more answers

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.