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2 years ago

I don’t know if this is correct !!!!!!!!!! Please answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

aleksley [76]2 years ago

7 0

Answer: They are related by the AAS postulate and they can be proven congruent.

Step-by-step explanation: You can see that one of the lines on each of the triangle has that little tick which means those lines are congruent. You can also see that for two of the angles one of them has one arc and the other has two arcs for BOTH triangles which makes those two angles congruent. Two angles and one side congruent makes the triangles congruent by the AAS postulate.

I hope I helped! :)

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The point B(1, 1) is rotated 90° counterclockwise around the origin. What are the co

Thepotemich [5.8K]

Given that the point B is (1,1) is rotate 90° counterclockwise around the origin.

We need to determine the coordinates of the resulting point B'.

Coordinates of the point B':

The general rule to rotate the point 90° counterclockwise around the origin is given by

$(x, y) \rightarrow(-y, x)$

The new coordinate can be determined by interchanging the coordinates of x and y and changing the sign of y.

Now, we shall determine the coordinates of the point B' by substituting (1,1) in the general rule.

Thus, we have;

Coordinates of B' = $(1,1) \rightarrow(-1,1)$

Thus, the coordinates of the resulting point B' is (-1,1)

3 0

3 years ago

WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)

IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0

3 years ago

He normal pulse rate of a 13-year-old is between 70 and 100 beats per minute. As part of a health program, the medical staff at

SVEN [57.7K]

From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.

Thus, interquatile range of the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10

Similarly, from the box plot, it can be seen that for grade 8 students,
The least value is 76 and the highest value is 97. The lower and the upper quartiles are 85 and 94 respectively while the median is 89.

Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9

The difference of the medians of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5

Therefore, the difference of the medians is about half of the interquartile range of either data set.

6 0

3 years ago

Read 2 more answers

7y-10>38 show your work

krek1111 [17]

Answer:

Step-by-step explanation:

7×10=70

70-10=60

60 > 38

4 0

3 years ago