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LUCKY_DIMON [66]
3 years ago
13

Find the annual interest rate paid on this loan:

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Step-by-step explanation:

we know this

interest = $81; principal = $10,800; time = 1 month

r = i/p*r

r = 81/10,800 * 1

<em><u>r = 0.0075</u></em>

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Jensen has an above ground pool in the shape of a regular octagon. Opposite sides are 25 feet apart and each side is 10.4 feet l
Studentka2010 [4]

Answer:

<u>Given</u>: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

  • 8(1/2 × 10.4 × 12.5)
  • 520ft²

Volume of pool = 520ft² × 3ft

  • 1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

  • 1560 × 7.5
  • 11700

So, <u>Correct choice</u> - [D] 11,700.

5 0
3 years ago
(−4)−(−2)–{(−5)–[(−7)+(−3)–(−8)]}<br> please i need this done really soon
sertanlavr [38]

Answer: 15



Step-by-step explanation: I cant say the steps because I need to pay

5 0
3 years ago
Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y = x squared + 2
Charra [1.4K]

Answer:

Step-by-step explanation:

y = x² + 2x - 5

d. D: all real numbers R: (y greater-than-or-equal-to negative 6)

6 0
3 years ago
In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg
siniylev [52]

Answer:

\dfrac{AP}{PC}=\dfrac{3}{5}

\dfrac{BN}{CN}=\dfrac{3}{5}

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

  • angle A is the common angle, so \angle MAP\cong \angle DAC by reflexive property;
  • angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,

so

\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}

Consider triangles ACB and PCN. In these triangles,

  • angle C is the common angle, so \angle ACB\cong \angle PCN by reflexive property;
  • angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,

so

\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}

4 0
3 years ago
Help i'll make you the brainliest
9966 [12]

Answer:

D) b = \frac{S-2ac}{2a + 2c}

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = \frac{S-2ac}{2(a + c)}

Finally, multiply out the denominator:

b = \frac{S-2ac}{2a + 2c}

7 0
4 years ago
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