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3 years ago

Find the annual interest rate paid on this loan:

Mathematics

1 answer:

yuradex [85]3 years ago

7 0

Step-by-step explanation:

we know this

interest = $81; principal = $10,800; time = 1 month

r = i/p*r

r = 81/10,800 * 1

r = 0.0075

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Jensen has an above ground pool in the shape of a regular octagon. Opposite sides are 25 feet apart and each side is 10.4 feet l

Studentka2010 [4]

Answer:

Given: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

8(1/2 × 10.4 × 12.5)
520ft²

Volume of pool = 520ft² × 3ft

1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

1560 × 7.5
11700

So, Correct choice - [D] 11,700.

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3 years ago

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sertanlavr [38]

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3 years ago

Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range. y = x squared + 2

Charra [1.4K]

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Step-by-step explanation:

y = x² + 2x - 5

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3 years ago

In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg

siniylev [52]

Answer:

$\dfrac{AP}{PC}=\dfrac{3}{5}$

$\dfrac{BN}{CN}=\dfrac{3}{5}$

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

angle A is the common angle, so $\angle MAP\cong \angle DAC$ by reflexive property;
angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

$\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,$

$\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}$

Consider triangles ACB and PCN. In these triangles,

angle C is the common angle, so $\angle ACB\cong \angle PCN$ by reflexive property;
angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

$\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,$