4/15ths of 49. I know the answer but I can’t seem to figure out how to do the work so if someone could tell me the steps on how
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Answer:
<h2>28% probability that every student in the group is a girl.</h2>Step-by-step explanation:
In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.
So, the probability when the first girl is being picked is:
Because among the total 9 students, there are 7 girls.
Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:
Then, the probability of the third girl:
The fourth girl probability:
Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):
Therefore, there's 28% probability that every student in the group is a girl.
N=0,8,16,24,...; because when n=8k 
then n/8 is natural number.
So the smallest value of n is 0.
So the smallest value of n is 0.