The answer is D because they are both legs and you are looking for the hypotenuse
The number of integer values of n for which the value 4000 × (0.4)ⁿ is an integer is; 9
<h3>How to find the integer values in algebra?</h3>
We are given the expression;
4000 × (0.4)ⁿ
This can also be expressed as;
4000 × (²/₅)ⁿ which can further be expressed in exponent form as;
(2⁵ × 5³) × (²/₅)ⁿ = 2⁽⁵ ⁺ ⁿ⁾ × 5⁽³ ⁻ ⁿ⁾
Since this expression is an integer, we need:
1) 5 + n ≥ 0 for which n ≥ -5
2) 3 - n ≥ 0 for which n ≤ 3
Taking the intersection gives;
-5 ≤ n ≤ 3
Thus;
Number of Integer Values = 3 - (-5) + 1 = 9
Read more about Integer Values at; brainly.com/question/17695139
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When Your Integers Are Negative Or Positive. Some Of Them Are Rational Numbers witch Those Are Factors and Decimals. Positives Are Number That Are Larger For A Example 2,3,4,5 and So On. In the Other Hand Negatives smaller For Example There -2,-3,-4,-5 and So On.
Answer:
40.5
Step-by-step explanation:
if y varies jointly as the square of x and the cube of z and inversely as the square root of w, this is expressed as;
y ∝ x²z³/√w
y = kx²z³/√w
If x = 2, z = 2, y = 12 and w = 64
Substitute;
12 = k (2)²(2)³/√64
12 = 32k/8
12 = 4k
k = 12/4
k = 3
To get y when x = 1, z = 3, and w = 4.
y = 3 (1)²(3)³/√4
y = (3*27)/2
y = 81/2
y = 40.5
Hence the value of y is 40.5
