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alukav5142 [94]
3 years ago
13

HELP ASAP! See screenshot for question and answers:

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer:

2 mosquitoes would be killed on the sixth day.

Step-by-step explanation:

To model this situation of exponential decay, we use y=a(b)^x. Y would represent the mosquitoes killed after so many days of the spraying, a would be the initial amount of mosquitoes, b would be how much it decreases each time, and x is days after the spraying. To get the original amount of mosquitoes, we multiply 2400 by 4 and get 9600. I did this because I noticed that each day, you can divide the previous number by 4. Then, our b would be 1/4 because 600 is one fourth of 2400, 150 is one fourth of 600, and so on. Then, I put this into my calculator: 9600(1/4)^6. This gave me 2.34375 but you would round to 2 mosquitoes. Hope this helps :)

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What is the X intercept and Y intercept of this graph
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Suppose you earned extra money by having a part-time job. You open up a bank account in order to save your money. Your body acts similar to a bank account—you can “deposit” and “store” energy.

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The base of a solid is bounded by the curve y = sqrt (x+1) the x-axis and the line x = 1. the cross sections, taken perpendicula
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See attached for a sketch of some of the cross sections.

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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3 years ago
Which logaritnmic equation equivalent to the exponential equation below 5c=125
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I assume you meant to write 5^c = 125. The equivalent logarithmic expression for this would be ㏒₅125=c.
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