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Jobisdone [24]
3 years ago
10

I'm struggling but any way to make it easy ??,

Mathematics
1 answer:
Katen [24]3 years ago
4 0
B.Squares is your answer

Hope this helps.

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For each annual rate of change, find the corresponding growth or decay factor. -55 %
Marizza181 [45]

The decay factor for the annual rate of change of - 55 % is 0.45.

A quantity must vary by a specific percentage each time period in order for growth or decay to be exponential.

With the function displayed to the right, you may represent exponential growth or decay.

A(x) = a( 1 + r)ˣ

Where A is the amount after x time periods, a is the initial amount, x is the number of time periods, and r is the rate of change.

Now, we have the annual rate of change as:

r = - 55 % = - 55 / 100 = - 0.55

From the function A(x) = a( 1 + r)ˣ , the corresponding factor is 1 + r.

So, let B = 1 + r

B = 1 + r

B = 1 + (- 0.55)

B = 1 - 0.55

B = 0.45

Now, the value of B is less than 1 therefore, the corresponding decay factor is 0.45.

Learn more about growth and decay factor here:

brainly.com/question/16702201

#SPJ4

6 0
2 years ago
Ill give brainliest, please
Flura [38]

Answer:

1st One goes to the third one

2nd one goes to the 1st one

3rd one goes to the 4th one

and the 4th one goes to the 2nd one

7 0
3 years ago
What’s the answer to this exponent question? Step by step
Irina18 [472]
You have to use the distributive property for the numerator on both equations.

8 0
3 years ago
Why is P(A) •P(B/A) = P(B) • P(A/B)<br> HELP ME QUICK ASAP
Gala2k [10]

Answer:

rawrrrrrrrrrrrrrrrrr

Step-by-step explanation:

Why is P(A) •P(B/A) = P(B) • P(A/B)

P/B + P = A

P/B/P

- A

6 0
2 years ago
Four friends go to the movies and pay $11 per ticket. They also each buy a snack
Setler79 [48]

Answer:

Each snack combo costed $8

Step-by-step explanation:

4 friends* 11 per ticket = $44 for four tickets

76 - 44 = $32 spent on all the snack combos

$32 ÷ 4 friends = $8 spent on each snack combo

So, each snack combo costed $8

Hope this helps!

6 0
2 years ago
Read 2 more answers
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