Question

Pablo randomly picks three marbles from a bag of seven marbles (four red ones, two green ones, and one yellow one). how many outcomes are there in the event that pablo picks one marble of each color?\

Answer 1

Green probability is 2/7
red probability is 4/7
yellow probability is 1/7

the answer I got was 33 outcomes

Answer 2

Answer:

8

Step-by-step explanation:

We are given that

Total marbles =7

Number of red marbles=4

Number of two green marbles=2

Number of yellow marbles=1

We have to find the total number of outcomes are there in the event that Pablo picks one marbles of each color when Pablo randomly picks three marbles from a bag.

Combination formula:$nC_r=\frac{n!}{r!(n-r)!}$

Using combination formula

Total number of outcomes=$4C_1\times 2C_1\times 1$

Total number of outcomes=$\frac{4!}{3!}\times \frac{2!}{1!1!}$

Total number of outcomes==$\frac{4\times 3!}{3!}\times 2\times 1=8$

Hence, total number of outcomes are there in event that Pablo picks one marbles of each color=8