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blondinia [14]
3 years ago
8

Could someone please explain! I cant figure it out.

Mathematics
1 answer:
qwelly [4]3 years ago
3 0

2^-2 = 1/2^2

so: (1/2^2)*(12*3)-5^3

simplify: (1/4)*36-125

36*(1/4) = 36/4 so: 9-125

subtract: -116

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The probability of guessing correctly on 5 true- false questions is (3)". Express this probability as a fraction without exponen
Free_Kalibri [48]

3/5

Just do the 3 over the five

5 0
3 years ago
3.
loris [4]

(a) It looks like the ODE is

<em>y'</em> = 4<em>x</em> √(1 - <em>y </em>^2)

which is separable:

d<em>y</em>/d<em>x</em> = 4<em>x</em> √(1 - <em>y</em> ^2)   =>   d<em>y</em>/√(1 - <em>y</em> ^2) = 4<em>x</em> d<em>x</em>

Integrate both sides. On the left, substitute <em>y</em> = sin(<em>t </em>) and d<em>y</em> = cos(<em>t</em> ) d<em>t</em> :

∫ d<em>y</em>/√(1 - <em>y</em> ^2) = ∫ 4<em>x</em> d<em>x</em>

∫ cos(<em>t</em> ) / √(1 - sin^2(<em>t</em> )) d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>

∫ cos(<em>t</em> ) / √(cos^2(<em>t</em> )) d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>

∫ cos(<em>t</em> ) / |cos(<em>t</em> )| d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>

Since we want the substitutiong to be reversible, we implicitly assume that -<em>π</em>/2 ≤ <em>t</em> ≤ <em>π</em>/2, for which cos(<em>t</em> ) > 0, and in turn |cos(<em>t</em> )| = cos(<em>t</em> ). So the left side reduces completely and we get

∫ d<em>t</em> = ∫ 4<em>x</em> d<em>x</em>

<em>t</em> = 2<em>x</em> ^2 + <em>C</em>

arcsin(<em>y</em>) = 2<em>x</em> ^2 + <em>C</em>

<em>y</em> = sin(2<em>x</em> ^2 + <em>C </em>)

(b) There is no solution for the initial value <em>y</em> (0) = 4 because sin is bounded between -1 and 1.

7 0
3 years ago
40% of<br> a number is 8 more than the<br> number<br> Which is the number
salantis [7]
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X+y=40
Y=8 + x
Substituting the second equation into the first:
X+(8+x)=40
2x+8=40
2x=32
Smaller number: x=16
Y=8+(16)
Large number: y=24
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$4.40. 5 divide by 20 is 4.00 then u have the 2dollars divided by 5 is 40 cents
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