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blondinia [14]
4 years ago
8

Could someone please explain! I cant figure it out.

Mathematics
1 answer:
qwelly [4]4 years ago
3 0

2^-2 = 1/2^2

so: (1/2^2)*(12*3)-5^3

simplify: (1/4)*36-125

36*(1/4) = 36/4 so: 9-125

subtract: -116

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Read 2 more answers
At what x value does the function given below have a hole?<br><br> f(x)=x+3/x2−9
S_A_V [24]

Answer:

hole at x=-3

Step-by-step explanation:

The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)

The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.

So anyways we have (x+3)/(x^2-9)

= (x+3)/((x-3)(x+3))

Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.

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