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3 years ago

Write a sentence explaining why all solutions of rational equation must be checked

Mathematics

1 answer:

algol [13]3 years ago

4 0

Answer:

Some found solutions may be extraneous, so they must all be checked in the original equation.

Step-by-step explanation:

All "solution" values that make any denominator of a rational expression zero must be excluded from the solution set. Every solution must be checked to make certain it is not excluded.

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Given: f(-x) = x - 7 and h(x) = 2x + 3

Nitella [24]

Answer:

if given f(-x)=x-7, then f(h(x))=-2x-10

or if given f(x)=x-7, then f(h(x))=2x-4

Step-by-step explanation:

if given f(-x)=x-7

f(-x)=x-7 => f(-(-x))=(-x)-7 =>f(x)= -x-7

f(h(x))=f(2x+3)= -(2x+3)-7 = -2x-3-7 = -2x-10

if given f(x)=x-7

f(h(x))=f(2x+3)=2x+3-7=2x-4

6 0

3 years ago

How does multiplying a vector by a scalar value of -pi change the vector?

Dmitriy789 [7]

I believe the answer to your question is A

6 0

4 years ago

Which unit would be best for measuring the thickness of a coin?

ser-zykov [4K]

Answer:

centimeter is the best to meause with

5 0

3 years ago

Shania had $20 to spend on seven raffle tickets. After buying them she had $6. How much did each raffle ticket cost?

kogti [31]

Answer:

Step-by-step explanation:

Total money Shania was having = $20.

After buying raffle tickets she was having a total of $6.

Thus ,

The money she spent on the raffle tickets = Money she was having initially -

Money she was having after

purchasing tickets .

= $20 - $6

= $14.

Thus She spent a total of $14 on tickets .

Now , number of tickets she bought = 7.

So, cost of each ticket = $\frac{Money spent}{Number of tickets}$ = $\frac{14}{7}$

= $2.

Thus , each ticket costs $2 for Shania.

7 0

3 years ago

Find the circumference of a circle with an area of 113.1 in square

nlexa [21]

Step-by-step explanation:

$Circumference = 2r\pi \\Area = r^2\pi$

In order for us to find the circumference, we need to find the radius from the given area by rearranging the area formula.

$r=\sqrt{\frac{A}{\pi } }$

$r=\sqrt{\frac{113.1}{\pi } }$

$r=\sqrt{36}$

$r=6$

Now that we have the radius, we can find the circumference.

$Circumference=2(6)\pi$

$Circumference=12\pi$

$Circumference=37.68$

So, when given 113.1 in sq for the area, the circumference of the circle is 37.68 in.

7 0

4 years ago