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ivolga24 [154]
3 years ago
13

you are making beaded bracelets for your for your friends. you want to use 30 beads for each bracelet want to use no more than 1

45 beads. write an inequality that models this situation. can you make 4 bracelets?
Mathematics
1 answer:
Softa [21]3 years ago
5 0

30(x)<=145 and yes she would be able to make 4 bracelets because 30 x 4 = 120 and that is less than 145

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A set of four cards consists of two red cards and two black cards. The cards are shuffled thoroughly, and I am dealt two cards.
Delvig [45]
25% because if you have 4 cards which would equal 100% and you are dealt 2 you have a 25% chance of getting any of the 4. (25x4=100)
But, if you are talking about probability of color it would be 50% because if you have 2 red cards and the total deck is 4 cards, then that is already half of the deck. And if you have 2 black cards then that makes up the other half. but if you are talking individually like Red 1 and Red 2 and Black 1 and Black 2 separating them would create a 25% probability. So, x= 25% (infivudually) or 50% (by color)
4 0
2 years ago
Please help! this is due today and this is the only question left!!
Soloha48 [4]

Answer:

13.73 sq mm

Step-by-step explanation:

Area of Square - Area of Circle = Area of Shaded Region

if radius of circle is 4 then diameter is 8

the diameter is the same as the length of each side of the square

so area of square = 8² or 64

Area of Circle = 16π

64 - 16π ≈ 13.73

7 0
3 years ago
One-third the sum of 6 and 3
irina [24]

Step-by-step explanation:

1/3(6+3)

= 1/3(9)

= 3

......

8 0
2 years ago
Read 2 more answers
how many ways are there to adjust two quantities so that they are in a given proportional relationship? Explain your reasoning.
dolphi86 [110]
The question is, "how many ways ...". 

There are as many ways to solve a math problem as you can think of. (Some are shorter or easier than others.)

Essentially, an infinite number.
7 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
2 years ago
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