Answer:
a. The Sun is 110.24 cm.
b. The distance of the nearest star at 4.24 light years is 3.1586 × cm.
Explanation:
Given a scale :
12700 Km : 1 cm
a. How large is the Sun of diameter 1.4 × Km?
Thus using the given scale, we have to compare the diameter of the Sun to that of the Earth.
=
= 110.2362
The Sun is 110.24 cm.
b. how far away is the nearest star at a distance of 4.24 light-years on this scale?
A light year is a term that is used to express the total distance that light would travel in an empty space in a year.
One light year = 9.461 × Km
So that,
4.24 light years = 4.24 × 9.461 × Km
= 40.11464 × Km
Using the given scale,
= 3.1586 ×
The distance of the nearest star at 4.24 light years is 3.1586 × cm.
CORRECT ANSWER:
a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.
STEP-BY-STEP EXPLANATION:
The complete question from book is
According to Figure 9.6, what is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?
a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.
b- Signaling molecules that bind to cell-surface receptors lead to cellular responses restricted to the cytoplasm; signaling molecules that bind to intracellular receptors lead to cellular responses restricted to the nucleus.
c- Cell-surface receptors bind to specific signaling molecules; intracellular receptors bind any signaling molecule.
d- Cell-surface receptors typically bind to signaling molecules that are smaller than those bound by intracellular receptors.
e- None of the other answer options is correct.
Answer:
The gain in velocity is 0.37m/s
Explanation:
We need solve this problem though the conservation of momentum. That is,
Using the equation to find ,
Using the conservation of energy equation, we have,
Now this energy over the cannonball
The gain in velocity is 0.37m/s