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3 years ago

A model rocket weighing 4.9 N launches from a pad. How much work does the little rocket engine do in the first 4 meters

Physics

1 answer:

USPshnik [31]3 years ago

5 0

Answer:

Work done by the little rocket engine = 19.6 Joules.

Explanation:

We know that work = force x displacement.

Force = weight of rocket = 4.9 N

Displacement = 5 meter.

So work done by the little rocket engine = Weight of rocket x displacement.

Work done by the little rocket engine = 4.9 x 4 = 19.6 J

Work done by the little rocket engine = 19.6 Joules.

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The electric field between the plates of a parallel-plate capacitor is horizontal, uniform, and has a magnitude E. Asmall object

kirza4 [7]

Answer:

$m = 0.041 kg$

Explanation:

As we know that the small particle is in equilibrium at an angle of 16 degree with the vertical

so here we can use force balance in vertical and horizontal direction

$T cos\theta = mg$

$T sin\theta = qE$

now from above equation we have

$T = \sqrt{(mg)^2 + (qE)^2}$

also by division of above two equations we have

$\frac{qE}{mg} = tan\theta$

$qE = mg tan\theta$

now from above equation again

$T = \sqrt{(mg)^2 + (mg)^2 tan^2\theta}$

$T = mg sec\theta$

$0.420 = m(9.81) sec 16$

$m = 0.041 kg$

3 0

3 years ago

Professor Stefanovic is spinning a bucket of water by extending his arm and rotating his shoulder in class to show the effects o

anyanavicka [17]

Answer:

a ) 2.368 rad/s

b) 3.617 rad/s

Explanation:

the minimum angular velocity that Prof. Stefanovic needs to spin the bucket for the water not to fall out can be determined by applying force equation in a circular path

i.e

$F_{inward } = F_G + F_T$ ------ equation (1)

where;

$F_{inward} = m *a_c$

$F_{inward} = m*r* \omega^2$

Also

$F_G = m*g$

$F_T = 0$ since; that is the initial minimum angular velocity to keep the water in the bucket

Now; we can rewrite our equation as :

$mr \omega^2= mg + 0\\\omega^2 = \frac{m*g}{m*r}\\\omega^2 = \frac{g}{r}\\\omega = \sqrt{\frac{g}{r} \ \ } ------ equation \ \ \ {2}$

So; Given that:

The rope that is attached to the bucket is lm long and his arm is 75 cm long.

we have our radius r = 1 m + 75 cm

= ( 1 + 0.75 ) m

= 1.75 m

g = acceleration due to gravity = 9.81 m/s²

Replacing our values into equation (2) ; we have:

$\omega = \sqrt{ \frac{9.81}{1.75}}\\\omega = 2.368 \ rad/s$

b) if he detaches the rope and spins the bucket by holding it with his hand ; then the radius = 0.75 m

∴

$\omega = \sqrt{ \frac{9.81}{0.75}}\\\omega = 3.617 \ rad/s$

4 0

4 years ago

What type of energy conversion occurs at the moment fireworks explode?

Paladinen [302]

chemical energy converts into light, heat and sound energy

6 0

4 years ago

Read 2 more answers

Because weight is a measurement of the amount of gravity pulling on an object, weight is considered a ______. Question 18 option

Andrews [41]

Answer: Force I believe.

6 0

2 years ago

Which rational number could be graphed between 0 and 1?A number line going from negative 5 to positive 3 in increments of 1.Nega

vovikov84 [41]

In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

$\begin{gathered} \text{negative one-half:} \\ -\frac{1}{2}=-0.5 \\ \\ \text{one}-\text{fourth:} \\ \frac{1}{4}=0.25 \\ \\ \text{three}-\text{halves:} \\ 3\cdot\frac{1}{2}=\frac{3}{2}=1.5 \\ \\ 1.75 \end{gathered}$

Looking at the numbers in their decimal form, we can see that the number between 0 and 1 is one-fourth, therefore the correct option is the second one.

7 0

1 year ago