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3 years ago

A force of 31 N south is used to accelerate an object uniformly from rest to 8 m/s in 22 s. What is the mass of the object?

Physics

2 answers:

natulia [17]3 years ago

8 0

Answer:

Explanation:

Givens

F = 31 N

vi = 0

vf = 8 m/s

t = 22 seconds

m = ?

Formula

F = m ( vf - vi)/t

Solution

31 = m (8 - 0) / 22 Multiply both sides by 22

31 * 22 = 8 * m

8m = 682 Divide by 8

m = 682 / 8

m = 85.25

harina [27]3 years ago

4 0

this question is centered around newtons second law f=ma

First you need to find the acceleration

$acceleration = \frac{8 - 0}{22}$

that gives you 0.36 recurring(on both numbers) m/s²

mass= force ÷ acceleration

$mass = \frac{31}{0.36recurring}$

mass= 85.25 kg

if you want to check

f=ma

85.25 × 0.36 recurring (remember its on both numbers not just 6) = 31 N

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A boy starting from rest, slides down a snowy hill on a sled. He travels 174.19 m to the bottom of the hill. He accelerates

AfilCa [17]

Answer:

11.6 s

Explanation:

We can use equation of motiom to solve this

$s = ut + \frac{1}{2} a {t}^{2 } \\ 174.19 = (0)t + \frac{1}{2} (2.61){t}^{2 } \\ t = 11.6s$

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3 years ago

A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee

GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

$d=v_ot+\frac{1}{2}at^2$

Now, we transform the total distance the cat would need to travel:

$90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m$

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

$t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots$

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

$1.5m=v_0(\frac{10}{3}s)+\frac{1}{2}(-\frac{9.8m}{s^2})(\frac{10}{3}s)^2\Rightarrow1.5m=v_0(\frac{10}{3}s)+(-\frac{490}{9}m)$ $\Rightarrow\frac{1007}{18}m=v_0(\frac{10}{3}s)\Rightarrow v_0=\frac{1007}{60}\frac{m}{s}\Rightarrow v_0=16.78333\ldots$

So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

5 0

2 years ago

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:

fgiga [73]

Here, we are required to determine which combination of molecules will produce ammonia with no leftovers.

Option A: 2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.

First, it is important to know that both Nitrogen and Hydrogen used in the production of ammonia are diatomic.

Secondly, Nitrogen and Hydrogen are in the ratio 1 : 3.....

As such, the coefficient of hydrogen should be thrice that of Nitrogen to ensure that there are no leftovers.

Therefore, option A which has:

2N2 and 6H2 is the correct combination of molecules that will produce ammonia with no leftovers.

Read more:

brainly.com/question/24396848

8 0

3 years ago

The highest barrier that a projectile can clear is 24.7 m, when the projectile is launched at an angle of 23.0 Â° above the hori

ra1l [238]

Initial velicity Vo.

Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec

4 0

3 years ago

guys pls help which one is it

Crazy boy [7]

Answer:

a mixture

since it had the power to separate as the question says

8 0

3 years ago