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Anvisha [2.4K]
3 years ago
9

A worker drives a spike into a rail tie with a 2.00-kg sledgehammer. This caused the internal energy of the hammer and spike to

increase by 1,250 Joules. If one half of the hammer’s kinetic energy is converted into the internal energy of the hammer and spike, what was the hammer’s speed when it hit the spike? In your computations, for the mass, use the mass of the hammer only.
Physics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

50 m/s

Explanation:

half of the hammer’s kinetic energy = internal energy of the hammer and spike

½ (½ mv²) = U

v² = 4U/m

v² = 4 (1250 J) / (2.00 kg)

v = 50 m/s

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If the primary coil of a transformer has 200 turns and is supplied with 120 v ac power, how many turns must the secondary coil h
Oduvanchick [21]
The ratio of the turns to the voltage should be equal
i.e: 200/120 = t/12
so the secondary coil should have 20 turns
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If you are trying to loosen a stubborn screw from a piece of wood with a screwdriver and fail, should you find a screwdriver for
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A fatter handle. This allows you to provide more torque to the screw, which should eventually loosen it.

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PHYSICS PLEASE HELP
vaieri [72.5K]

1.)Answer:

The correct answer is C.

Explanation:

Displacement is a vector quantity so it may be either positive or negative. As per convention, acceleration taken as positive when moves downward direction. But, in our case, acceleration towards downward taken as negative, so displacement should also be negative because negative sign only indicate its downward direction.

2.) Answer

The correct answer is C. The time won't change, but horizontal distance will double.

Explanation:

First case

velocity = v = 20 m/s

Height = h = 10 m

We need to calculate time (t) and horizontal distance (x)

using 2nd equation of motion

h = vt + 0.5 gt²

As initial vertical velocity is 0. So

h = 0.5(9.8)t²

It can be see that time does not depends on initial velocity, so it won't change

to calculate x

x = vt

It can be see that horizontal distance will double because depends on velocity.

3.)Question

Illustration:

Day 1: 10 km west and spent night at A.

Day 2: 10 km west and night in a tent B.

Day 3: 20 km west and then they turned around and went back to the home because Jerry left his allergy medicine.

Day 4: 30 km North to the point D.

Answer

The correct answer is C.

Explanation:

On Day 1, Day 2 and Day 3, they move towards west 40 km from home and then turned back to home because Jerry forget his medicine. Thus the total distance is 80 km but the displacement is zero because displacement is the measure from initial to final position. As initial and final position is same at the end of 3rd day so displacement is zero. Fourth day, They move towards north 30 km and hence total distance is 110 km. And total displacement is only 30 km.

4.) Answer:

The correct Answer is A.

Explanation:

To calculate horizontal distance (x), we only need to find the horizontal component of velocity that is

vₓ = v Cos (70°)

vₓ = 41 m/s

As we know that x = vₓ t

So,

x = 41t

5.) Answer

The correct Answer is B.

Explanation:

Displacement is a vector quantity so it depends on direction. As Sally moves 10m forward and then 5m backward, So his total displacement is 5m. While the distance is scalar quantity independent of direction. So the total distance covered by Sally is 15m which is 10m greater than the displacement.  

6.)Answer

The correct answer is A.

Explanation:

Consider

horizontal(h)= 6m

vertical = Xm

Hypotenuse(H) = ?

Angle = 37°

As we know that

H×Cos∅ = h

So,

H = h ÷ Cos(∅)

  = 6 ÷ Cos(37)

H = 7.5 m    

7.) Answer:

The correct answer is D.

Explanation:

In projectile motion, horizontal distance depends on initial velocity and angle with ground. So as the player increase the velocity of the ball, more distance will be covered. As far as he increase the angle upto 45° with the ground, the horizontal distance will increase. That's why the player should increase the ball's initial velocity and kick it at a 45° angle.

8.)Answer:

The correct Answer is B.

Explanation:

Consider

Vector A  = 3m

Vector B  = 4m

Angle = ?

As the angle ∅ is created between vectors C and A.

we know that

tan∅ = vertical ÷ horizontal

tan∅ = 4 ÷ 3

∅ = tan⁻¹ (1.33)

∅ = 53.1°

9.) Answer:

The correct Answer is C.

Explanation:

Projectile motion depends on initial velocity and initial angle with ground. As far as we increase the velocity of the ball, more distance will be covered. As it also depends on angle, So as far as we increase the angle up to 45° with the ground, the horizontal distance will increase. But when the angle is above 45°, increasing angle decrease the horizontal distance.

10.) Answer:

The correct Answer is B.

Explanation:

Given data :

∅ = 20°

initial velocity = 40 m/s

As we need to find the vertical component of velocity

So, initial upward velocity = initial velocity × Sin∅ = 40 × Sin 20°

             initial upward velocity = 13.68 m/s

11.)Answer:

The correct Answer is B.

Explanation:

The projectile motion depends on the angle with the horizontal.As far as we increase the angle up to 45° with the ground, the distance will increase. But when the angle is above 45°, increasing angle decrease the horizontal distance.

12.) Answer:

The correct answer is D.

Explanation:

Given data

Initial speed = V₀ =40 m/s

angle = 60°

g = 9.81 m/s²

First we need to find initial vertical velocity (V)

V = V₀ Sin∅

V = 34.64 m/s

3rd equation of motion

2gh = V₁² - V²

As we need to find maximum height so at highest point vertical final velocity (V₁) = 0

So,

h = V² ÷ 2g

 = 34.64² ÷ 2×9.81

                              h = 61.2 m

13.) Answer:

The correct answer is C.

Explanation:

A bird flying in the air is 3D motion as the bird move up, down, right, left all the possible direction. A leaf falling from a tree is also a 3D motion because a leaf never fall in absolute vertical manner. A lady bug crawling on a soccer ball also 3D. If lady bug crawling on a plane like floor then it is 2D but now lady bug crawling on soccer ball which is in spherical shape so it is also 3D motion. Only train travelling along a track is 2D because train cannot move up and down and the track of train is in a plane. So it is 2D motion.  

6 0
3 years ago
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A projectile is fired from the ground (you can assume the initial height is the same as the ground) in a field so there are no o
Cerrena [4.2K]

Answer:

A) 112 m. B) 27.2 m C) 41.1 m/s i + 13.4 m/s j  D) 43.2 m/s

Explanation:

A) Once fired, no external forces act on the projectile in the x-direction, so it keeps moving to the right at constant speed, which is the projection on the x-axis of  the initial velocity vector:

v₀ₓ = v₀* cos 33º = 49 m/s* cos 33º = 41.1 m/s

In the y-direction, the component of the velocity can be found as the projection of v₀ on the y-axis, as follows:

v₀y = v₀* sin 33º = 49 m/s* sin 33º = 26.7 m/s

Both velocities are independent each other, as no one has a projection on the other.

In the vertical direction, the  projectile is in free fall all time, under the influence of gravity , which accelerates it downward.

So, at any time, in the vertical direction, the velocity can be calculated as follows:

vfy = v₀y -g*t (same equation as for an object thrown upwards)

When the object is at its maximum height, the velocity, in the vertical direction, will be momentarily zero, so we can find the time when this happens as follows:

vfy= 0 ⇒ v₀y = g*t ⇒ t = v₀y / g = 26.7 m/s / 9.8 m/s² = 2.72 s

As the time is the same for both movements, we can replace this value in the expression for the displacement x at constant speed, as follows:

x = v₀ₓ* t = 41.1 m/s* 2.72 s = 112 m

B) Like above, as the time is the same for both movements, we can find the time for the instant that the projectile hit the wall, as follows:

x = v₀ₓ* t ⇒ 55. 8 m = 41.1 m/s * t

⇒ t = 55. 8 m / 41.1 m/s = 1.36 s

We can replace this value of t in the equation for the vertical displacement, as follows:

Δy = v₀y*t -1/2*g*t² = (26.7m/s*1.36s) - 1/2*9.8m/s²*(1.36s)² = 27.2 m

C) The velocity of the projectile, at any time, has two components, one horizontal and one vertical.

As explained above, x-component is constant, equal to v₀x:

vx = v₀x i = 41.1 m/s i

For vy, we can apply acceleration definition, using the value of v₀y and t that we have just found:

vfy = voy - g*t = 26.7 m/s - 9.8m/s*1.36 sec = 13.4 m/s

vfy = 13.4 m/s j

v = 41.1 m/s i + 13.4 m/s j

D) Finally, in order to get the speed of the projectile when it hit the wall, we need just to find the magnitude of the velocity, as we get the magnitude of any vector given its vertical and horizontal components:

v = √(41.1 m/s)² +(13.4 m/s)² =43.2 m/s

5 0
3 years ago
A thin beam of light of wavelength 50 μm (in the infrared portion of the em spectrum) goes through
Brut [27]

Solution :

Given :

Wavelength of the thin beam of light, λ = 50 μm

Distance of the screen from the slit, D = 3.00 m

Width of the fringe, Δy = ±8.24 mm

Therefore, width of the slit is given by :

$d=\frac{n \lambda D}{\Delta y}$

  $=\frac{2 \times 50 \times 10^{-9} \times 3}{2 \times 8.24 \times 10^{-3}}$

  = 0.000018203 m

  = 0.0182 mm

  = 0.018 mm

The intensity of light is given by :

$I=I_0\left(\frac{\sin \beta /2}{\beta/ 2}\right)^2$   , where $\beta=\frac{2 \pi D \sin \theta}{\lambda}$

$I=I_0\left(\frac{\sin \frac{\pi d \sin \theta}{\lambda}}{\frac{\pi d \sin \theta}{\lambda}}\right)^2$

$I=I_0\left(\frac{\sin \frac{\pi d y}{D\lambda}}{\frac{\pi d y}{D\lambda}}\right)^2$

Now, $\frac{dy}{D \lambda} = \frac{8.24 \times 10^{-3}\times 0.018 \times 10^{-3}}{4 \times 50\times 10^{-9}\times 4}$

               = 0.1854

               ≈ 0.18

$I=I_0\left(\frac{\sin 0.56}{0.56}\right)^2$

  $=I_0 \times 0.81$

  = 2  x0.81

  $= 1.62 \ W/m^2$

 

6 0
3 years ago
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