<span>We know that pressure is the force applied into a surface, in our case the wall of the room, so then first we will calculate the surface of this wall:
S = 2.2 * 3.2 = 7.04 m2
Then we also know the atmospheric pressure in normal conditions is 1 atm. That is the same 1 atm = 101325 Pascals or 101325 N/m2
Now we need to use the formula : P = F/S where P is pressure, F is force and S is surface to calculate the force:
F = P * S = 101325 * 7.04 = 713,328 Newtons
Conclusion: the force acts on the wall due the air inside the room is 713,328 N</span>
Answer:
a) Final velocity of second bowling pin is <u>2.5m/s</u>.
b) Final velocity of second bowling pin is <u>3 m/s</u>.
Explanation:
Let 'm' be the mass of both the bowling pin -
m = 1.5 kg
Initial velocity of first bowling pin -
In any type of collision between two bodies in horizontal plane , momentum is conserved along the line of impact.
a) Since , initial velocity of second bowling pin is 0 m/s -
Initial momentum ,
Final velocity of first bowling pin , [Considering initial direction of motion of the first bowling pin to be positive]
Let be the final velocity of the second bowling pin.
∴ Final momentum ,
.
Now ,
∴
∴ = 3 - 0.5 = 2.5 m/s
∴ Final velocity of second bowling pin is 2.5 m/s.
b) Since , initial velocity of second bowling pin is 0 m/s -
Initial momentum ,
Final velocity of first bowling pin , [given][Considering initial direction of motion of the first bowling pin to be positive]
Let be the final velocity of the second bowling pin.
∴ Final momentum ,
.
Now ,
∴
∴ = 3 - 0 = 3 m/s
∴ Final velocity of second bowling pin is 3 m/s.
1)
<Solve using the formula which is:
Mass=Density×Volume
2)
3)
(Length × Width × Height)
(Answer=7.5)