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pashok25 [27]
4 years ago
8

Someone please help! It is a few science questions. Fairly easy!

Physics
2 answers:
borishaifa [10]4 years ago
3 0
1) 0.92 * 100 = 92 <Solve using the formula which is:
Mass=Density×Volume
M=D*V

2) 3.98 ml

3) V=L*W*H (Length  × Width × Height)

5*2*4=40
\frac{300}{40} =7.5 (Answer=7.5)
maks197457 [2]4 years ago
3 0
So for the first one the answer is : 0.92 * 100 = 92 
the second one the answer is 8.80 :)
and for the third one the density is 7.5 
i hope this is helpful 
have a nice day 
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The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating havin
nadya68 [22]

Answer:

The range of angles is from 17.50° to 31.76°

Explanation:

The diffraction grid equation is as follows:

dsen\theta=m\lambda

Clearing for \theta

sen\theta=\frac{m\lambda}{d}

\theta=sen^{-1}(\frac{m\lambda}{d})

where \theta is the angle, m is the order, in this case m=1, \lambda is the wavelength, and d is defined as follows:

d=\frac{1}{resolution}

and since the resolution is 750 lines/mm wich is the same as 750lines/1x10^{-3}m

d will be:

d=\frac{1}{750lines/1x10^{-3}m}=\frac{1x10^{-3}m}{750lines}=1.33x10^{-6}m

wich is the distance between each line of the diffraction grating.

substituting the values for m and d:

\theta=sen^{-1}(\frac{(1)\lambda}{(1.33x10^{-6}m)})

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

\theta=sen^{-1}(\frac{(400x10^{-9})}{(1.33x10^{-6}m)})=17.50

and

\theta=sen^{-1}(\frac{(700x10^{-9})}{(1.33x10^{-6}m)})=31.76

The range of angles is from 17.50° to 31.76°

3 0
3 years ago
How can you prevent static sparks while filling your boat's fuel tank?
dangina [55]
To prevent static sparks that could occur while you fill fuel is that, a person who is filling the tank should remember that the nozzle of the fuel pump hose should always be in connected or in contact to the tank. This will prevent static sparks from happening to the boat that is going to be used and prevent harm to the person using or refilling the fuel.
4 0
3 years ago
Read 2 more answers
2. Two spherical objects with radii 1 m have masses of 1.5 kg and 8.5 kg. They are separated by a
____ [38]

Answer:

They are separated by a distance of 18 m. Find the gravitational attraction between them. r= 1 m r= 1 m 18 m. Mass = 1.5 kg. Mass = 8.5 kg.

6 0
2 years ago
In the experiment, “Rolling Along”, which ball had the greater mass?
olga2289 [7]

Answer:

b

Explanation:

4 0
3 years ago
An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of w
allochka39001 [22]

Answer:

Q_a=330 cal

Q_w=6000cal

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

      Q_c=M_c *C_c*( \triangle T)

Therefore imputing variables we have

      Q_a=50g *0.22*50-20  

      Q_a=330 cal

b) Heat energy on water

Generally the formula for mathematically solving heat gain

       Q_w=M_w *C_w*( \triangle T)

Therefore imputing variables we have

       Q_w=200 *1* 50-204

       Q_w=6000cal

7 0
3 years ago
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