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Liula [17]
2 years ago
8

Find the value of |-4 3| · 8

Mathematics
1 answer:
S_A_V [24]2 years ago
6 0
<span>|-4 3| is called an absolute value, anything in an absolute value becomes a positive number. So the </span><span>|-4 3| becomes a 43. We rewrite the problem 43 * 8 = 344.</span>
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What is the simplified expression for 4 power 4 multiplied by 4 power 3 over 4 power 5
MaRussiya [10]
4^4 * 4^3
------------
    4^5

= 4^7 / 4^5

= 4^(7-5)

= 4^2   =  16   Answer
5 0
3 years ago
If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
If anyone doesn't mind helping may you plz help me
Verdich [7]

Answer:

SAS

Step-by-step explanation:

Please let me know if this doesn't help. I'm trying my best to relearn this so I can help you.

3 0
2 years ago
Read 2 more answers
Consider the polynomial equation x(x -3)(x +6)(x -7)=0. Which of the following are zeros of the equation? Select all that apply.
grigory [225]
(0,0), (3,0), (-6,0), and (7,0)
4 0
3 years ago
The sum of a certain number and a second number is -42. The first number minus the second number is 52. find the numbers
julia-pushkina [17]
Let the first number be x and decide number be y
therefore x+y = -42
also. x-y = 52 using the process of elimination
we get: 2x = 10
we divide both sides by 2, which gives us x=5
then we substitute the value of x in the first equation
that gives us. 5+y = -42
thus. y = -47
8 0
3 years ago
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