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Ira Lisetskai [31]
2 years ago
10

A study at a college in the west coast reveals that, historically, 45% of their students are minority students. if a random samp

le of size 75 is selected, the probability is ________ that between 30% and 50% of the students in the sample will be minority students.
Mathematics
1 answer:
Evgesh-ka [11]2 years ago
5 0
100 percent because 45 % is always in between 30 and 50 %
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Mrs. Dixon had 1/2 of a cherry pie leftover. She split the leftover pie evenly between her children, and each child got 1/6 of a
AVprozaik [17]
1/2 = 3/6
Each children got 1/6
3/6 - 1/6x = 0
3/6 = 1/6x
X = 3, she has 3 children
8 0
2 years ago
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I need to find side x of this 30 60 90 triangle i think with special right triangle methods
zvonat [6]

This is a 30-60-90 triangle and we can apply rules to easily identify the hypotenuse of this triangle, which is denoted by <em>x</em>.

The length of the longer side of the triangle is given in the problem. To solve the hypotenuse of this triangle, let's solve first for the length of the shorter side of the triangle.

The shorter side can be solved by just dividing the length of the longer side by the square root of 3. Hence, we have

short=\frac{4}{\sqrt[]{3}}

Since we already have the values for the length of the shorter side and longer side, we can solve for the hypotenuse using the Pythagorean theorem.

\begin{gathered} c=\sqrt[]{a^2+b^2} \\ c=\sqrt[]{4^2+(\frac{4}{\sqrt[]{3}})^2} \\ c=\sqrt[]{16+\frac{16}{3}} \\ c=\sqrt[]{\frac{64}{3}} \\ c=\frac{8}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}} \\ c=\frac{8\sqrt[]{3}}{3} \end{gathered}

Hence, the value of hypotenuse for this right triangle is

x=\frac{8\sqrt[]{3}}{3}

4 0
8 months ago
What additional information would he need to prove the triangles are congruent using the Side-Angle-Side method?
garri49 [273]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.

∆ABC and ∆DEF has been drawn as shown in the attachment below.

We are given that \overline{AB} \cong \overline{DE} and also \overline{AC} \cong \overline{DF}.

In order to prove that ∆ABC \cong ∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.

The included angle has been shown in the ∆s drawn in the diagram attached below.

Therefore, the additional information that would be need is:

\angle A \cong \angle D

3 0
3 years ago
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aleksandr82 [10.1K]
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the unit rate is 3:5
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3 years ago
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Which equation represents the line that passes through the points (6,9) and (3.5)?
sukhopar [10]

the answer is y=2x-3

You can look at my work if you really need to

5 0
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