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cluponka [151]
3 years ago
6

What is the solution?

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

145

Step-by-step explanation:

steps in attached illustration

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12 and 13 please I’m giving 71 points
Pavlova-9 [17]

Answers and Step-by-step explanation:

12: The 5s are worth a lot more than the 2s. The 5s are worth fifty thousand and five thousand whereas the 2s are only worth two hundred and twenty.

13: She needs 4 forks (2000 - 1996 = 4)

    She needs 255 knives (2000 - 1745 = 255)

    She has 226 extra spoons ( 2116 - 2000 =  116)

5 0
3 years ago
Read 2 more answers
The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 5 to 4 . If there were
Kamila [148]
If there were 5 yes votes for every 4 no votes, there were 5 yes votes for every 9 total votes, so 5/9 of the 7911 votes were yes.  5/9*7911=4395.
7 0
2 years ago
The mean vitamin C level for 20 dogs was 7.6 milligrams per liter, with a standard deviation of 2.1 milligrams per liter.
SpyIntel [72]

Answer:  The mean increases.

Step-by-step explanation:

The value of 0.9 mg/L is very low compared to a means of 7.6 mg/L with a standard deviation of 2.1 mg/L.  It seems as though it is an outlier that is suffiently different from the others, and probably should be dropped from the data set.  That would do 2 things:  1) the stabdard deviation will likely decrease, indicating a more confident data set, and 2) the mean vitamin C level will increase.

5 0
2 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle's largest angle?
Rama09 [41]

1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)

400=81+169-234(cosA)   150=-234(cosA)

cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

6 0
3 years ago
Read 2 more answers
How do I do #1 ? Help!!
juin [17]

1) First find the multiplier.

Look at the 0 and 1st term you have 5 as the 0 and 3 as the 1st term.

2)Ask how do we get from 5 to 3?

  • We subtract 2 so the multiplier is -2

3)Lets make a linear equation: y=mx +b

  • m= multiplier or slope
  • x= Just equals x value
  • b= your starting value or the 0 term which is 5

4)Use the values that you have to create your equation.

  • y=-2x +5

Note:For the x value just plug in the x value from your table.

Ex.

  • y=-2(-10)+5
  • y=20+5
  • y=25

5 0
2 years ago
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