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boyakko [2]
3 years ago
5

Explain how you can use place value to describe how 0.05 and 0.005 compare

Mathematics
1 answer:
Dovator [93]3 years ago
3 0
.05 is larger than .005 because larger numbers are always to the left and smaller numbers are always to the right
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.08 is 10 times as much as
Mazyrski [523]
It is 10 times as much as .008

Do you see the pattern?
5 0
3 years ago
The Johnson twins were born four years after their older sister. This year, the product of the three siblings ages is exactly 34
svp [43]

Answer:

Step-by-step explanation:

Let age of each twin be x

let age of sister be s

So we can write:

x + 4 = s

The product of the 3 siblings ages is 3482 more than sum. We can write:

s*x*x=3482+(s+x+x)

This can be simplified as:

sx^2=3482+s+2x

We replace s with "x + 4" and solve:

(x+4)x^2=3482+x+4+2x\\x^3+4x^2=3486+3x\\x^3+4x^2-3x-3486=0\\x=14

<u>Note:</u> To solve this cubic, we used technology

Thus, we can say the twins are 14 years old

3 0
3 years ago
Operations with Fractions
Mila [183]

Answer:

option a or c

Step-by-step explanation:

hope it helps u

6 0
2 years ago
Read 2 more answers
Which lengths could be the sides of a triangle?
galina1969 [7]
345,354,354,341,098cm
5 0
3 years ago
The data below are the ages and systolic blood pressures (measured in millimeters of mercury) of 9 randomly selected adults. Wha
seraphim [82]

Answer:

\sum_{i=1}^n x_i =459

\sum_{i=1}^n y_i =1227

\sum_{i=1}^n x^2_i =24059

\sum_{i=1}^n y^2_i =168843

\sum_{i=1}^n x_i y_i =63544

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=24059-\frac{459^2}{9}=650

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=63544-\frac{459*1227}{9}=967

And the slope would be:

m=\frac{967}{650}=1.488

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{459}{9}=51

\bar y= \frac{\sum y_i}{n}=\frac{1227}{9}=136.33

And we can find the intercept using this:

b=\bar y -m \bar x=136.33-(1.488*51)=60.442

So the line would be given by:

y=1.488 x +60.442

And then the best predicted value of y for x = 41 is:

y=1.488*41 +60.442 =121.45

Step-by-step explanation:

For this case we assume the following dataset given:

x: 38,41,45,48,51,53,57,61,65

y: 116,120,123,131,142,145,148,150,152

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i =459

\sum_{i=1}^n y_i =1227

\sum_{i=1}^n x^2_i =24059

\sum_{i=1}^n y^2_i =168843

\sum_{i=1}^n x_i y_i =63544

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=24059-\frac{459^2}{9}=650

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=63544-\frac{459*1227}{9}=967

And the slope would be:

m=\frac{967}{650}=1.488

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{459}{9}=51

\bar y= \frac{\sum y_i}{n}=\frac{1227}{9}=136.33

And we can find the intercept using this:

b=\bar y -m \bar x=136.33-(1.488*51)=60.442

So the line would be given by:

y=1.488 x +60.442

And then the best predicted value of y for x = 41 is:

y=1.488*41 +60.442 =121.45

3 0
3 years ago
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