A biased example: Asking students who are in line to buy lunch
An unbiased example: Asking students who are leaving/going to lunch(<em>NOT buying </em><em>lunch</em><em />).
But in this case, the answer choices can be... confusing.
Don't panic! You're given numbers and, of course, your use of logic.
Answer choice A: 100 students grades 6-8
Answer choice B: 20-30 students any <em>one</em> grade<em></em><em>
</em>Answer choice C: 5 students
<em></em>Answer choice D: 50 students grade 8
An unbiased example would be to choose students from <em>any grade.</em> So we can eliminate choices B and D.
Now, the question wants to <em>estimate how many people at your middle school buy lunch.</em> This includes the whole entire school, and if you are going to be asking people, you aren't just going to assume that if 5 people out of 5 people you asked bought lunch, the whole school buys lunch.
So, to eliminate all bias and/or error by prediction, answer choice A, the most number of students, is your answer.
To get the answer we can use proportion
10 large ------------- 14 small
x large -------------- 35 small
crossmultiply
10*35=x*14
350=14x /:14
350:14=14x:14
25=x-its the answer
Answer: A. As x → ∞, f(x) → ∞, and as x → –∞, f(x) → ∞.
Answer:
x= -4 and y= 27/6
Step-by-step explanation:
-(8x + 6y = -5) which converts to -8x -6y = 5
10x + 6y = -13
simplify from there
-8x + 10x = 2x ; -6y + 6y = 0 ; 5 - 13 = -8
soo, now you have
2x = -8
x = -4
then, plug in to find y
8(-4) + 6y = -5
-32 + 6y = -5 add 32 on both sides
6y = 27 divide both sides by 6
y= 27/6 or 4.5
