<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
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Answer:
its 55
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
I believe if you multiply 850×2= 1700.
Multiply 850×3..
That would equal to 2550.
