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3 years ago

Factor this quadratic expression: a2 - 2a - 15

Mathematics

2 answers:

Mumz [18]3 years ago

8 0

A² - 2a - 15
= a² - 5a + 3a - 15
= a(a-5) + 3(a-5)
= (a-5)(a+3)

Sliva [168]3 years ago

7 0

A^2-2a-15

1. Ask: Which two numbers add up to -2 and multiply to -15?
-5 and 3

2. Rewrite the expression using the above
(a-5)(a+3)

Have a nice day :D

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3 years ago

What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

$x=\frac{-7+\sqrt{17}} {4}$

and

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7 0

2 years ago

Three times as many children as adults attended a concert on Saturday. An adult ticket cost $7 and a child’s ticket cost $3. The

Ierofanga [76]

For this case we propose a system of equations:

x: Let the variable representing the number of children in the concert

y: Let the variable representing the number of adults at the concert

According to the assistance we have:

$x = 3y$

According to the cost we have:

$3x + 7y = 6000$

Substituting the first in the second equation we have:

$3 (3y) + 7y = 6000\\9y + 7y = 6000\\16y = 6000\\y = \frac {6000} {16}\\y = 375$

Thus, the concert was 375 adults.

On the other hand we have:

$x = 3 (375) = 1125$

Thus, the concert was 1125 children.

In total they were:

$375 + 1125 = 1500$ people

ANswer:

The concert was 1500 people

3 0

3 years ago