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3 years ago

Hello - I have one last question that I think you might be able to help me with. Thanks~

Mathematics

2 answers:

Nata [24]3 years ago

7 0

Let slant height be s
Height = 38yd. = h
Side = 42yd. = a

S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.

Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²

Volgvan3 years ago

6 0

Hello Gary!

In Short, The Correct Answer would be: Option "D". 3647 yd^2

Because: Base edge = 42 and Height = 38

So then, AL=a√a^2+4h^2=42·√42^2+4·38^2≈3646.99328. (3647 rounded up)

AL≈3646.99

Hope this Helps! Have A Wonderful Day! :)

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4 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let $r$ represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

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$\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}$

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$\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)$

$\frac{dV}{dt}=252\pi$

Using $\pi=3.14$

$\frac{dV}{dt}=252(3.14)$

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Thus rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

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