<span>0.000487=4.87⋅<span>10<span>−4.............</span></span></span>
Answer:
0.2196
Step-by-step explanation:
Given that
Mean = 4.56 million visitors per day
Standard deviation = 820,000 visitors per day
According to the given situation the calculation of probability is shown below:-
Here we will find the value of P (3 ≤ X ≤ 4)



= 0.2483 - 0.0287
= 0.2196
Therefore the probability that the web site has between 3 million and 4 million visitors in a single day is 0.2196
Answer:
30y+14
Step-by-step explanation:
add the values of all the sides together: (5y+4) + (5y+4) + (10y+3) + (10y+3) = (5y + 5y + 10y + 10y) + (4 + 4 + 3 + 3)= 30y + 14
84 is your awnser if i helped i hope im in fourth grade so dont judge