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vagabundo [1.1K]

3 years ago

14

6372(52836y)+46x=665x(637y+57)

1 answer:

alex41 [277]3 years ago

7 0

Answer:

$x=\frac{336670992y}{423605y+37859};\quad \:y\ne \:-\frac{37859}{423605}$

Step-by-step explanation:

$6372\left(52836y\right)+46x=665x\left(637y+57\right)\\6372\cdot \:52836y+46x=665x\left(637y+57\right)\\336670992y+46x=665x\left(637y+57\right)\\336670992y+46x=423605xy+37905x\\336670992y+46x-336670992y=423605xy+37905x-336670992y\\46x=423605xy+37905x-336670992y\\46x-\left(423605xy+37905x\right)=423605xy+37905x-336670992y-\left(423605xy+37905x\right)\\-423605xy-37859x=-336670992y\\-x\left(423605y+37859\right)=-336670992y\\$ $\frac{-x\left(423605y+37859\right)}{-\left(423605y+37859\right)}=\frac{-336670992y}{-\left(423605y+37859\right)}\\x=\frac{336670992y}{423605y+37859};\quad \:y\ne \:-\frac{37859}{423605}$

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2 and 3/8 times 1 and 5/7 pls help!

mina [271]

Answer:

4 1/14

Step-by-step explanation:

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3. $\frac{228}{56}$

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3 years ago

Which is the best estimate for the lenght of a real couch? Answer has to be in meters.

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4 years ago

In the diagram shown, /Il m, m

Dmitry_Shevchenko [17]

Answer:

29°

Step-by-step explanation:

Angles 1 and 8 are alternate exterior angles where a transversal crosses parallel lines, so are congruent.

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5 0

4 years ago

Simplify the square root (Picture provided)

Elodia [21]

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$\sqrt {8 ^ {17}}$

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Substituting:

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By definition of properties of powers and roots we have:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

So:

$8 ^ {\frac {16} {2}} * \sqrt {8}\\8 ^ 8 * \sqrt {8}$

So we have to:

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Option A

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3 years ago

How to tell if two lines are perpendicular

katrin [286]

ANSWER

The two lines are perpendicular if $m_1 \times m_2 = - 1$

EXPLANATION

Given two lines:

$y=m_1x+b_1$

and

$y=m_2x+b_2$

We can tell wether these two lines are perpendicular to each other using their slopes.

If the product of their slopes is -1, the then the two line are perpendicular.

For example:

The line

$y = 2x + 6$

has slope

$m_1= 2$

and the line

$y = - \frac{1}{2} x + 1$

has slope

$m_2 = - \frac{1}{2}$

The product of the two slopes is

$m_1 \times m_2 = 2 \times - \frac{1}{2}$

This implies that:

$m_1 \times m_2 = - 1$

Therefore the two lines are perpendicular.

4 0

3 years ago