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vagabundo [1.1K]
2 years ago
14

6372(52836y)+46x=665x(637y+57)

Mathematics
1 answer:
alex41 [277]2 years ago
7 0

Answer:

x=\frac{336670992y}{423605y+37859};\quad \:y\ne \:-\frac{37859}{423605}

Step-by-step explanation:

6372\left(52836y\right)+46x=665x\left(637y+57\right)\\6372\cdot \:52836y+46x=665x\left(637y+57\right)\\336670992y+46x=665x\left(637y+57\right)\\336670992y+46x=423605xy+37905x\\336670992y+46x-336670992y=423605xy+37905x-336670992y\\46x=423605xy+37905x-336670992y\\46x-\left(423605xy+37905x\right)=423605xy+37905x-336670992y-\left(423605xy+37905x\right)\\-423605xy-37859x=-336670992y\\-x\left(423605y+37859\right)=-336670992y\\\frac{-x\left(423605y+37859\right)}{-\left(423605y+37859\right)}=\frac{-336670992y}{-\left(423605y+37859\right)}\\x=\frac{336670992y}{423605y+37859};\quad \:y\ne \:-\frac{37859}{423605}

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Write a word problem that could be solved with the equation c+1.02=13.48
USPshnik [31]
Here is your word problem →

A boy had $1.02 with him , his friend Chucky gave him some amount of money and now he has $13.48 . How much money did Chucky gave to that boy.

Solution →

Let the money given by Chucky be c.

Therefore , According to question →

c + 1.02 = 13.48

or, c = 13.48 - 1.02

or, c = 12.46

Answer → Chucky gave him $12.46

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8 0
3 years ago
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iren2701 [21]

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
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The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
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Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
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3 years ago
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Answer:

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slope=-1/2

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