Answer:
It got cut off, but the approximate y intercept is 3 and slope intercept form is
y = x + 3 and I used the points 0,3 and 3,6 to calculate the slope using the slope equation y1 - y2/x1 - x2
Hope this helped and brainliest please!
Answer:
a) 5.83 cm
b) 34.45°
Step-by-step explanation:
a) From Pythagoras theorem of right triangles, given right triangle ABC:
AB² + BC² = AC²
Therefore:
AC² = 5² + 3²
AC² = 25 + 9 = 34
AC = √34
AC = 5.83 cm
b) From triangle ACD, AC = 5.83 cm, AD = 4 cm and ∠A = 90°.
From Pythagoras theorem of right triangles, given right triangle ACD:
AD² + AC² = DC²
Therefore:
DC² = 5.83² + 4²
DC² = 34 + 16 = 50
DC = √50
DC = 7.07 cm
Let ∠ACD be x. Therefore using sine rule:

Answer:
The point does not lie on the line
Step-by-step explanation:
Find the slope of the equation with rise/run
This gets you -1/-1 = 1
The equation will be y = x + 3, given the y intercept at (0, 3)
Plug in the point (2, 6) to see if it works in the equation
6 = 2 +3
6
5
The point does not lie on the line