Question

Find the length of the hypotenuse of a right triangle whose legs are 3 and sqrt 2

Answer 1

To begin with, you need to use Pythagorean Theorem (a^2+b^2=c^2)
3 becomes 9
The square root of 2 which is 1.4142135623731
becomes 2
Add those 2 numbers together and you get 11
The square root of 11 is 3.3166247903554
The equation you get is- 3^2+square root of 2^2=3.3166247903554

The length of the hypotenuse is 3.3166247903554

~Revilla03

Answer 2

Answer:

$\sqrt{11}$ units.

Step-by-step explanation:

We are asked to find the length of the hypotenuse of a right triangle whose legs are 3 and $\sqrt{2}$.

We will use Pythagoras theorem to solve our given problem.

$\text{Leg}^2+\text{Leg}^2=\text{Hypotenuse}^2$

$3^2+(\sqrt{2})^2=\text{Hypotenuse}^2$

$9+2=\text{Hypotenuse}^2$

$11=\text{Hypotenuse}^2$

Switch the sides:

$\text{Hypotenuse}^2=11$

Upon taking square root of both sides, we will get:

$\text{Hypotenuse}=\sqrt{11}$

Therefore, the length of the hypotenuse of the given right triangle is $\sqrt{11}$ units.