Distributing same key numbers
Answer:
i)W = 2500 / T
ii) W = 500 Tons
iii) grad W(10°) = - 25î
iv) The formulation is not practical
Step-by-step explanation:
i) Write an equation describing the use of coal
As use of coal is inversely proportional to the average monthly temperature
if W is use of coal in tons/per month then
W(t) = k / T where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions
k = ?? we know that when T = 25° W = 100 tons the by subtitution
W = k/T 100 = k /25 k = 2500 Tons*degree
Then final equation is:
W = 2500 / T
ii) Find the amount of coal when T = 5 degrees
W = 2500 / 5
W = 500 Tons
iii)
The inverse proportionality implies that W will decrease as T increase.
The vector gradient of W function is:
grad W = DW(t)/dt î
grad W = - 2500/T² î
Wich agrees with the fact that W is decreasing.
And when T = 100°
grad W(10°) = - 2500/ 100 î ⇒ grad W(10°) = - 25î
iv) When T = 0 The quantity of coal tends to infinite and the previous formulation is not practical
Answer:
the answer is 80 i think
Step-by-step explanation:
bc dependng on 2lw+2lh+2hw, formula 8 and 10 would be length and width
Lets say
8=width
10=lenght
3in=height
u would do
2 x l x w + 2 x l h + 2 x h x w=
2 x 10 x 8 + 2 x 10 x 3 + 3 x 8=
160 + 60 + 48+=
268 is the sa
pls brainliest and more points :0
X = 250 mg tabs
y = 500 mg tabs
2200x + 1800y = 39200....multiply by -1
2200x + 2200y = 44000
--------------------------------
-2200x - 1800y = - 39200 (result of multiplying by -1)
2200x + 2200y = 44000
--------------------------------add
400y = 4800
y = 4800/400
y = 12...... the 500 mg tabs (y) costs $ 12 per bottle
2200x + 2200y = 44000
2200x + 2200(12) = 44000
2200x + 26400 = 44000
2200x = 44000 - 26400
2200x = 17600
x = 17600/2200
x = 8 <== the 250 mg tabs (x) costs $ 8 per bottle
Answer:
An equivalent fraction is 5/6
Step-by-step explanation:
In order to find this, divide both parts of the fraction by 7.
35/7 = 5
42/7 = 6
Now we can put this back together as a fraction.
5/6