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My name is Ann [436]
2 years ago
9

Can someone help me with this please? Thank you!

Mathematics
1 answer:
Finger [1]2 years ago
5 0

Answer:

528 cm²

Step-by-step explanation:

First I would calculate the area of the side rectangles:

20 x 9 = 180 cm²

There are two identical rectangles on both sides so i would x2

180 x 2 = 360 cm²

The area of the middle rectangle:

6 x 20 = 120 cm²

The area of the triangles:

Area of a triangle = (Base x Height)/2

8 x 6 = 48

48 ÷ 2 = 24

There are two identical triangles on the bottom and the top so x2

24 x 2 = 48

Now add all the values up:

360 + 120 + 48 = 528 cm²

I hope this helps!

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If y varies directly as x, and y = 75 when X = 25. Find x when y=21 PLEASE HELP ASAP
user100 [1]
I think x would equal 7 because when y=75 and x=25, x is one third of y so one third of 21 is 7
6 0
3 years ago
Bobby and Rick are in a 16​-lap race on a​ one-mile oval track.​ Bobby, averaging 94 ​mph, has completed six laps just as Rick i
Reptile [31]

Answer: Hello!

first let's note the things we already know:

there is a 16- lap race and the oval has one mile of length, then each of the laps has a length of one mile, and the whole race has 16 miles in total

Bobby averages 94 mph and already did 6 laps ( or 6 miles)

then we could write the Bobby equation as B(t) = 6 miles + 94mph*t

where t represents the time in hours.

now we could see how much time Bobby needs to end the race:

B(x) = 6mi + 94mph*x = 16mi

94mph*x = 16mi - 6mi = 10mi

x = (10/94)h = 0.106h

so Bobby needs 0.106 hours to finish the race, and we want to know which velocity Rick should have in order to reach the end of the race at the same time as Bobby.

Rick is starting the race, so he needs to do 16 miles in 0.106 hours, and as we know velocity is distance over time; so the average velocity of Rick is:

V = 16mi/0.106h = 150.9mph

Now let's see the hint:

Bobby does 8 miles in:

94*t = 8

t = 8/94 = 0.085 hours

and Rick does 10 miles in:

150.9*t = 10

t = 10/150.9 = 0.066 hours

wich is clearly different times, so maybe the hint is wrong.

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3 years ago
Someone help please!!!
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