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zalisa [80]
3 years ago
5

A right triangle has legs with the lengths of 2 and 5, find the length of the hypotenuse

Mathematics
1 answer:
Volgvan3 years ago
3 0

Answer:

\sqrt{29}\ units

Step-by-step explanation:

we know that

In a right triangle

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the hypotenuse (the greater side)

a and b are the legs (perpendicular sides)

In this problem we have

a=2\ units\\b=5\ units

substitute

c^2=2^2+5^2

c^2=29

c=\sqrt{29}\ units

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The standard form of 0.0000035
azamat
In scientific notation, the answer is 3.5*10^-6 .

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3 years ago
ST has endpoints Y(-2, -4) and T (6, 8). Find the coordinates of the midpoint of ST
storchak [24]

add up the X values and y values and divide by two

X=(-2+6)/2=2

Y=(-4=8)/2=2

5 0
3 years ago
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Please help me!
ruslelena [56]
I agree with you because theta could be acute or obtuse, and if obtuse, negative value.
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3 years ago
3/4 and 16/20 equivalent
Sergeeva-Olga [200]

1.55

3/4 and 16/20 equivalent = 3/4 + 16/20 = (?)

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7 0
2 years ago
Which statement describes the behavior of the function f(x)=3x/4-x?
Oksana_A [137]

Answer:

The  graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

f(x)=\frac{3x}{4-x}

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{4-x}

Taking x common from the denominator.

\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{x(\frac{4}{x}-1)}

Cancel out common factor x.

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Apply limits.

\lim_{x\rightarrow \infty}f(x)=\frac{3}{\frac{4}{\infty}-1}

\lim_{x\rightarrow \infty}f(x)=\frac{3}{0-1}

\lim_{x\rightarrow \infty}f(x)=-3

Therefore the  graph approaches –3 as x approaches infinity.

7 0
3 years ago
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