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Oksana_A [137]
4 years ago
6

Add or subtract the following mixed numbers. First change each mixed number to an equivalent improper fraction. Then find a comm

on denominator, and proceed as before. Leave your answer as an improper fraction. Be sure your answers are reduced to lowest terms. 1 4/9 + 3 1/3 =
Mathematics
2 answers:
riadik2000 [5.3K]4 years ago
8 0

Answer:

43/9

Step-by-step explanation:

The given fraction is

1\frac{4}{9}+3\frac{1}{3}

Let us convert the mixed fraction into equivalent improper fraction.

1\frac{4}{9}=\frac{13}{9}

And, the second fraction becomes

3\frac{1}{3}=\frac{10}{3}

Now, we find the LCD. The LCD is 9

Now, we make each denominator equal to LCD, which is 9. So we multiply the numerator and denominator of second fraction with 3.

\frac{13}{9}+\frac{10\times3}{3\times3}\\\\=\frac{13}{9}+\frac{30}{9}

Now, since the denominator is equal. Hence, we can directly add numerators.

\frac{13+30}{9}\\\\=\frac{43}{9}

Therefore, the simplified expression is 43/9

elena-14-01-66 [18.8K]4 years ago
7 0
1 (4/9) = 13/9... 3 1/3 = 10/3
13/9 + 10/3 you must first have equal denominators (bottom numbers)
13/9 + 30/9 = 43/9 or 4 7/9
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If f(x) = 3x - 1 and g(x) = x + 2, find (f+ g)(x).
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4x+1

Step-by-step explanation:

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3 years ago
A Bank offers an annual simple interest rate of 8% on home improvement loans. Tobias borrowed $17,000 over a period of 2 years.
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We first find out the amount in dollars of interest accrued after 2 years  time.

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Interest = 1700 × 0.08 × 2

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6 0
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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

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So it has only 1 real number solution.

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So it has 2 real number solutions.

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b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

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5. a=3, b=5, c=3

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Thus it does not has real solutions.



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3 years ago
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